在点击事件中,我想在后面的代码中显示一个弹出窗口,但是我的弹出窗口没有显示?
void PopupDisplay_Tap(object sender, System.Windows.Input.GestureEventArgs e)
{
if (sender != null)
{
p = new Popup
{
Width = 480,
Height = 580,
HorizontalAlignment = System.Windows.HorizontalAlignment.Center,
VerticalAlignment = System.Windows.VerticalAlignment.Center
};
Border b = new Border();
b.BorderBrush = new SolidColorBrush(Colors.Gray);
b.BorderThickness = new Thickness(2);
b.Margin = new Thickness(10, 10, 10, 10);
p.Child = b;
p.IsOpen = true;
}
}
答案 0 :(得分:1)
认为你正在尝试弹出一个顶级控件,就像Pivot
一样非常错误。
如果它是Grid
,它会弹出没有问题。要解决此问题,您必须将其添加到与Pivot相同的视觉级别,如下所示:
<Grid x:Name="ContentPanel" Margin="0,0,0,0">
<phone:Pivot x:Name="MainDisplay">
<!-- more code -->
</phone:Pivot>
</Grid>
然后在你的代码隐藏
// I made with a thickness of 100, so we can see the border better
Popup p;
p = new Popup
{
Width = 480,
Height = 580,
VerticalOffset = 0
};
Border b = new Border();
b.BorderBrush = new SolidColorBrush(Colors.Red);
b.BorderThickness = new Thickness(100);
b.Margin = new Thickness(10, 10, 10, 10);
b.HorizontalAlignment = System.Windows.HorizontalAlignment.Stretch;
b.VerticalAlignment = System.Windows.VerticalAlignment.Stretch;
p.Child = b;
// add it to the same level as the pivot to over ride pivot
this.ContentPanel.Children.Add(p);
p.IsOpen = true;