Question

我正在创建一个LWJGL策略游戏，我正在实施多人游戏。

现在游戏正在生成一个具有不同平铺类型的世界。

我认为我现在应该开始实施网络，让服务器生成世界，并且所有客户加入下载世界并加载它（即使游戏几乎不可玩），以便更容易实现更高级的东西稍后的。现在来问题了！

我正在观看由these制作的有关网络实施的DesignsbyZephyr教程，但我收到此错误：

java.net.BindException: Address already in use: Cannot bind
    at java.net.DualStackPlainDatagramSocketImpl.socketBind(Native Method)
    at java.net.DualStackPlainDatagramSocketImpl.bind0(Unknown Source)
    at java.net.AbstractPlainDatagramSocketImpl.bind(Unknown Source)
    at java.net.DatagramSocket.bind(Unknown Source)
    at java.net.DatagramSocket.<init>(Unknown Source)
    at java.net.DatagramSocket.<init>(Unknown Source)
    at java.net.DatagramSocket.<init>(Unknown Source)
    at com.tdd12.eotu.net.GameServer.<init>(GameServer.java:22)
    at com.tdd12.eotu.Game.<init>(Game.java:39)
    at com.tdd12.eotu.Game.main(Game.java:121)
Exception in thread "Thread-3" java.lang.NullPointerException
    at com.tdd12.eotu.net.GameServer.run(GameServer.java:37)

当我用相同的端口开始游戏两次时。这听起来很奇怪，不是吗？

我不知道为什么，也许是因为我对网络编程不是很有经验（因为你可能已经理解过了）。

以下是我使用的代码：
（代码放在类和包中，因此它们格式正确。我只是没有在这里写出来）

GameServer.java：

// The socket
private DatagramSocket socket;
// The main game
private Game game;

// The constructor
public GameServer(Game game) {
    // Assign variables
    this.game = game;
    try {
        this.socket = new DatagramSocket(9527);
    } catch (SocketException e) {
        e.printStackTrace();
    }
}

// Run the thread
public void run() {
    while(true) {
        // The data to include in the packet (data to send)
        byte[] data = new byte[1024];
        // The packet to send
        DatagramPacket packet = new DatagramPacket(data, data.length);
        // Recieve data from the server
        try {
            socket.receive(packet);
        } catch (IOException e) {
            e.printStackTrace();
        }
        // Get the message
        String message = new String(packet.getData());
        // Print the message
        System.out.println("CLIENT [" + packet.getAddress().getHostAddress() + ":" + packet.getPort() + "] > " + new String(packet.getData()));
        // If the message is equal to "ping"
        if(message.trim().equalsIgnoreCase("ping")) {
            // Send back a message with the text "pong"
            sendData("pong".getBytes(), packet.getAddress(), packet.getPort());
        }
    }
}

// Send data to the server
public void sendData(byte[] data, InetAddress ipAddress, int port) {
    // Create a new packet with the inputed data
    DatagramPacket packet = new DatagramPacket(data, data.length, ipAddress, port);
    // Send the packet to the server
    try {
        socket.send(packet);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

GameClient.java：

// The IP address
private InetAddress ipAddress;
// The socket
private DatagramSocket socket;
// The main game
private Game game;

// The constructor
public GameClient(Game game, String ipAddress) {
    // Assign variables
    this.game = game;
    try {
        this.socket = new DatagramSocket();
        this.ipAddress = InetAddress.getByName(ipAddress);
    } catch (SocketException | UnknownHostException e) {
        e.printStackTrace();
    }
}

// Run the thread
public void run() {
    while(true) {
        // The data to include in the packet (data to send)
        byte[] data = new byte[1024];
        // The packet to send
        DatagramPacket packet = new DatagramPacket(data, data.length);
        // Recieve data from the server
        try {
            socket.receive(packet);
        } catch (IOException e) {
            e.printStackTrace();
        }
        // Print the data
        System.out.println("SERVER > " + new String(packet.getData()));
    }
}

// Send data to the server
public void sendData(byte[] data) {
    // Create a new packet with the inputed data
    DatagramPacket packet = new DatagramPacket(data, data.length, ipAddress, 9527);
    // Send the packet to the server
    try {
        socket.send(packet);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

如果有人能帮助我，我会非常感激。谢谢！

Answer 1

正如Diptopol大坝所说，打电话给

DatagramSocket.close();

应用程序关闭前的

方法修复了问题。谢谢Diptopol大坝！

Java网络 - java.net.BindException

1 个答案: