各种标记范围内的标记百分比
我有一张看起来像这样的表
对于每个评估代码，我想创建一个查询，该查询返回某些标记范围内的标记百分比...例如
FileYear AssessmentCode MarkRange MarkPercentage
2014 11cpssdd 0-10 5.88
2014 11cpssdd 11-20 0
2014 11cpssdd 21-30 0
2014 11cpssdd 31-40 0
2014 11cpssdd 41-50 0
2014 11cpssdd 51-60 0
2014 11cpssdd 61-70 0
2014 11cpssdd 71-80 29.4
2014 11cpssdd 81-90 52.9
2014 11cpssdd 91-100 11.7
根本不确定如何做到这一点，并想知道是否有人能够提供帮助？提前感谢您的帮助。
5 个答案:
答案 0 :(得分：1)
您可以计算每个范围的SUM，然后计算整个SUM中此SUM的百分比。这是完整的工作示例：
SET NOCOUNT ON
GO
DECLARE @DataSource TABLE
(
[FileYear] CHAR(4)
,[AssessmentCode] CHAR(8)
,[StudentID] INT
,[Mark] TINYINT
)
INSERT INTO @DataSource ([FileYear], [AssessmentCode], [StudentID], [Mark])
VALUES ('2014', '11cpssdd', '34323', '75')
,('2014', '11cpssdd', '74666', '38')
,('2014', '11cpssdd', '87664', '34')
,('2014', '11cpssdd', '87576', '66')
,('2014', '11cpssdd', '23455', '87')
,('2014', '11cpssdd', '87654', '75')
,('2014', '11cpssdd', '98776', '75')
,('2014', '11cpssdd', '34543', '55')
,('2014', '11ecoeco', '87687', '89')
,('2014', '11ecoeco', '56466', '77')
,('2014', '11ecoeco', '34544', '45')
,('2014', '11ecoeco', '95554', '23')
,('2014', '11ecoeco', '22322', '56')
,('2014', '11ecoeco', '76557', '66')
SELECT [FileYear]
,[AssessmentCode]
,[MarkPercentage]
,[MarkRange] * 100 /[ALL] AS [MarkRange]
FROM
(
SELECT [FileYear]
,[AssessmentCode]
,SUM(IIF([Mark] BETWEEN 0 AND 10, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 11 AND 20, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 21 AND 30, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 31 AND 40, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 41 AND 50, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 51 AND 60, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 61 AND 70, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 71 AND 80, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 81 AND 90, [Mark], 0))
,SUM(IIF([Mark] BETWEEN 91 AND 100, [Mark], 0))
,SUM([Mark])
FROM @DataSource
GROUP BY [FileYear]
,[AssessmentCode]
) DataSource ([FileYear], [AssessmentCode], [0-10], [11-20], [21-30], [31-40], [41-50], [51-60], [61-70], [71-80], [81-90], [91-100], [ALL])
UNPIVOT
(
[MarkRange] FOR [MarkPercentage] IN ([0-10], [11-20], [21-30], [31-40], [41-50], [51-60], [61-70], [71-80], [81-90], [91-100])
)PVT
ORDER BY [FileYear]
,[AssessmentCode]
,[MarkPercentage]
SET NOCOUNT OFF
GO
检查此解决方案。请注意我们正在筛选特定的AssesmentCode。另外，如果您需要decimal格式的结果，只需在分割前投射[MarkRange]。
SET NOCOUNT ON
GO
DECLARE @DataSource TABLE
(
[FileYear] CHAR(4)
,[AssessmentCode] CHAR(8)
,[StudentID] INT
,[Mark] TINYINT
)
INSERT INTO @DataSource ([FileYear], [AssessmentCode], [StudentID], [Mark])
VALUES ('2014', '11CPSSDD', '34323', '93')
,('2014', '11CPSSDD', '74666', '93')
,('2014', '11CPSSDD', '87664', '90')
,('2014', '11CPSSDD', '87576', '90')
,('2014', '11CPSSDD', '23455', '89')
,('2014', '11CPSSDD', '87654', '86')
,('2014', '11CPSSDD', '98776', '84')
,('2014', '11CPSSDD', '34543', '84')
,('2014', '11CPSSDD', '87687', '84')
,('2014', '11CPSSDD', '56466', '83')
,('2014', '11CPSSDD', '34544', '82')
,('2014', '11CPSSDD', '95554', '80')
,('2014', '11CPSSDD', '22322', '79')
,('2014', '11CPSSDD', '76557', '78')
,('2014', '11CPSSDD', '76557', '77')
,('2014', '11CPSSDD', '76557', '76')
,('2014', '11CPSSDD', '76557', '70')
SELECT [FileYear]
,[AssessmentCode]
,[MarkPercentage]
,[MarkRange] * 100 /[ALL] AS [MarkRange]
FROM
(
SELECT [FileYear]
,[AssessmentCode]
,SUM(IIF([Mark] BETWEEN 0 AND 10, 1, 0))
,SUM(IIF([Mark] BETWEEN 11 AND 20, 1, 0))
,SUM(IIF([Mark] BETWEEN 21 AND 30, 1, 0))
,SUM(IIF([Mark] BETWEEN 31 AND 40, 1, 0))
,SUM(IIF([Mark] BETWEEN 41 AND 50, 1, 0))
,SUM(IIF([Mark] BETWEEN 51 AND 60, 1, 0))
,SUM(IIF([Mark] BETWEEN 61 AND 70, 1, 0))
,SUM(IIF([Mark] BETWEEN 71 AND 80, 1, 0))
,SUM(IIF([Mark] BETWEEN 81 AND 90, 1, 0))
,SUM(IIF([Mark] BETWEEN 91 AND 100, 1, 0))
,COUNT([Mark])
FROM @DataSource
WHERE [AssessmentCode] = '11CPSSDD'
GROUP BY [FileYear]
,[AssessmentCode]
) DataSource ([FileYear], [AssessmentCode], [0-10], [11-20], [21-30], [31-40], [41-50], [51-60], [61-70], [71-80], [81-90], [91-100], [ALL])
UNPIVOT
(
[MarkRange] FOR [MarkPercentage] IN ([0-10], [11-20], [21-30], [31-40], [41-50], [51-60], [61-70], [71-80], [81-90], [91-100])
)PVT
ORDER BY [FileYear]
,[AssessmentCode]
,[MarkPercentage]
SET NOCOUNT OFF
GO
答案 1 :(得分：0)
您可以使用CASE语句来有条件地选择您需要的内容。你需要一个用于MarkRange列，一个用于返回MarkPercentage。
答案 2 :(得分：0)
这不是确切的答案，但这应该对你有所帮助我不知道你是如何得到这个百分比的。所以我评论说你可以稍微调整一下来获得百分比。
CREATE TABLE #test
(
FileYear INT,
AssessmentCode VARCHAR(50),
StudentID INT,
Mark INT
)
INSERT INTO #test
VALUES ( 2014,'11cpssdd',34323,75),( 2014,'11cpssdd',74666,38 ),
( 2014,'11cpssdd',87664,34),( 2014,'11cpssdd',87576,66),
( 2014,'11cpssdd',23455,87),( 2014,'11cpssdd',87654,75),
( 2014,'11cpssdd',98776,75),( 2014,'11cpssdd',34543,55),
( 2014,'11ecoeco',87687,89),( 2014,'11ecoeco',56466,77),
( 2014,'11ecoeco',34544,45),( 2014,'11ecoeco',95554,23),
( 2014,'11ecoeco',22322,56),( 2014,'11ecoeco',76557,66)
;WITH cte
AS (SELECT DISTINCT 0 AS fst,
10 AS scd,
fileyear,
AssessmentCode
FROM #test
WHERE AssessmentCode = '11cpssdd'
UNION ALL
SELECT scd + 1 fst,
scd + 10,
fileyear,
AssessmentCode
FROM cte
WHERE scd < 100)
SELECT b.FileYear,
b.AssessmentCode,
CONVERT(VARCHAR(10), fst) + ' - '
+ CONVERT(VARCHAR(10), scd) MarkRange,
count(case when mark IS not null then 1 end) Range_Count
--(count(case when mark IS not null then 1 end)/10.0)*100 percentage
FROM cte b
LEFT JOIN(SELECT CASE
WHEN mark BETWEEN 0 AND 10 THEN '0 - 10'
WHEN mark BETWEEN 11 AND 20 THEN '11 - 20'
WHEN mark BETWEEN 21 AND 30 THEN '21 - 30'
WHEN mark BETWEEN 31 AND 40 THEN '31 - 40'
WHEN mark BETWEEN 41 AND 50 THEN '41 - 50'
WHEN mark BETWEEN 51 AND 60 THEN '51 - 60'
WHEN mark BETWEEN 61 AND 70 THEN '61 - 70'
WHEN mark BETWEEN 71 AND 80 THEN '71 - 80'
WHEN mark BETWEEN 81 AND 90 THEN '81 - 90'
WHEN mark BETWEEN 90 AND 100 THEN '90 - 100'
END [range],
FileYear,
mark,
AssessmentCode
FROM #test
WHERE AssessmentCode = '11cpssdd') a
ON CONVERT(VARCHAR(10), fst) + ' - '
+ CONVERT(VARCHAR(10), scd) = [range]
AND a.AssessmentCode = b.AssessmentCode
GROUP BY b.FileYear,
b.AssessmentCode,
CONVERT(VARCHAR(10), b.fst) + ' - '
+ CONVERT(VARCHAR(10), b.scd)
答案 3 :(得分：0)
- 为特定范围声明每个变量10个。
- 将光标放在＆＃39; MARK＆＃39;并将相对变量增加1。
- 算一算。变量=变量/ 17。
- 分别将变量更新为新列＆＃39; MARK RANGE＆＃39;。
- 祝你好运!!
答案 4 :(得分：0)
这是获得结果的另一种方法。
;WITH a AS
(
SELECT FileYear, AssessmentCode, MarkCount = COUNT(*)
FROM #1
GROUP BY FileYear, AssessmentCode
)
, b AS
(
SELECT FileYear, AssessmentCode, Tenth = (Mark - 1)/10 + 1, MarkCount = COUNT(*)
FROM #1
GROUP BY FileYear, AssessmentCode, (Mark - 1)/10 + 1
)
SELECT a.FileYear, a.AssessmentCode
, MarkPercentage = CONVERT(varchar(3), Tenth * 10 - IIF(Tenth=1,10,9)) + '-'
+ CONVERT(varchar(3), Tenth * 10)
, MarkRange = CONVERT(float, LEFT(100.0 * b.MarkCount / a.MarkCount, 4))
FROM a
JOIN b ON a.FileYear = b.FileYear AND a.AssessmentCode = b.AssessmentCode
ORDER BY a.FileYear, a.AssessmentCode
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