Question

我有一个使用acts_as_tree的ActiveRecord类。我正在尝试更新to_xml方法，以便在调用子记录的to_xml时，它将返回嵌套在parent / ancestor xml中的xml，以提供该资源的完全限定路径。作为一个例子，我有编译器，它是编译器/版本的父。编译器应该呈现为xml：

编译器/版本应呈现为

我试图通过传递一个full_qualified标志来做到这一点，但它死了'Builder :: XmlMarkup＃to_ary应该返回Array'

def to_xml（options = {}，＆amp; block） options [：fully_qualified] || = true options [：indent] || = 2 options [：builder] || = Builder :: XmlMarkup.new（：indent =＆gt; options [：indent]）

if options[:fully_qualified] and not parent.nil?

55：parent.to_xml（options）do | foo | relative_options = options.dup relative_options [：fully_qualfied] = false relative_options [：skip_instruct] = true relative_options.delete（：助洗剂）

    foo << to_xml(relative_options)
  end
else
  xml = options[:builder]
  xml.instruct! unless options[:skip_instruct]

66：xml.parameter（：name =＆gt; name，＆amp; block）结束端

该方法适用于编译器的情况，但编译器/版本失败：

/usr/lib/ruby/1.8/builder/xmlbase.rb:133:in method_missing' /usr/lib/ruby/1.8/builder/xmlbase.rb:133:in来电' /usr/lib/ruby/1.8/builder/xmlbase.rb:133:in _nested_structures' /usr/lib/ruby/1.8/builder/xmlbase.rb:57:in method_missing' app / models / parameter.rb:66:in to_xml' app/models/parameter.rb:55:in to_xml'

Answer 1

看来你不能在任何单一关联上调用to_xml。父和参数上的to_xml（两个has_one关系）都失败了，但是如果我使用find_by_id进行了查找，它就有效了：

def to_xml（options = {}，＆amp; block） my_options = options.dup my_options [：fully_qualified] = true除非my_options.has_key？（：fully_qualified） my_options [：only] = [：name]

if my_options[:fully_qualified] and not parent.nil?
   # do block here fails with 'Builder::XmlMarkup#to_ary should return Array'
   # if called as parent.to_xml, so call on explicit lookup of parent and
   # it works
   p = self.class.find_by_id(parent_id)
   p.to_xml(my_options) do |xml|
     relative_options = my_options.dup
     relative_options[:builder] = xml
     relative_options[:fully_qualified] = false
     relative_options[:skip_instruct] = true

     to_xml(relative_options, &block)
   end
else
  super(my_options, &block)
end

端

使用acts_as_tree获取完全限定树的to_xml

1 个答案: