Question

我一直在使用HTML和PHP进行以下简单的温度转换。这是我第一次尝试使用PHP而我似乎无法正确使用它。

我确信我的代码中有很多错误，所以请耐心等待！

这就是我所拥有的：

<!DOCTYPE HTML>

<html>
<head> 
      <title>Temp Conversion</title>
      <meta charset="utf-8">
<body>
      <form name="tempConvert" method="POST" action="<?php echo $_SERVER["PHP_SELF"]; ?>">

<table>
<tr>
    <td>Enter value to convert</td>
    <td><input type="text" name="valueConvert" id="valueConvert" size="15"></td>
</tr>

<tr>
    <td>Convert to:</td>
    <td><select name="convertType" id="convertType" size="1">
               <option disabled> Select a measurement type</option>
               <option value="celsius">Celsius</option>
               <option value="fahrenheit">Fahrenheit</option>
        </select>
    </td>
</tr>

<tr>
    <td><input type="submit" name="btnConvert" id="btnConvert" value="Convert"></td>
    <td><input type="reset" name="btnReset" id="btnReset" value="Reset"></td>
</tr>



</form>

<?php


$valueConvert = $_POST['valueConvert'];
$convertType = $_POST['convertType'];
function tempConvert($valueConvert, $convertType){
    if($convertType == "fahrenheit"){
       $conversion = ((9/5)*$valueConvert) +(32);
   }
    else if ($convertType == "celsius"){
       $conversion = ($valueConvert - 32) * (9/5);
   }
return $conversion;
echo "The initial temperature was $valueConvert. The new temperature is $conversion.";
}
?>

    </body>
</html>

我无法弄清楚如何将用户文本框输入和下拉列表选择传递给php函数。

Answer 1

你几乎把事情搞定了。你不是在调用这个函数。

你的echo语句出现在return语句之后，永远不会被执行。

做这样的事情会更好：

<?php

function tempConvert($valueConvert, $convertType)
{
   if($convertType == "fahrenheit"){
       $conversion = ((9/5) * $valueConvert) + (32);
   }
    else if ($convertType == "celsius"){
       $conversion = ($valueConvert - 32) * (5/9);
   }
   return $conversion;
}

$valueConvert = $_POST['valueConvert'];
$convertType = $_POST['convertType'];
$conversion = tempConvert($valueConvert, $convertType);
echo "The initial temperature was $valueConvert. The new temperature is $conversion.";

?>

Answer 2

首先，我在评论中写道，你忘了取消头标记，其次你需要检查转换按钮是否关闭，我修复你的转换功能，还不知道它的工作有多好，我不是专业的PHP，但希望它的工作原理:)

<html>
<head> 
      <title>Temp Conversion</title>
      <meta charset="utf-8">
</head>
<body>
      <form name="tempConvert" method="POST" action="<?php echo $_SERVER["PHP_SELF"]; ?>">

<table>
<tr>
    <td>Enter value to convert</td>
    <td><input type="text" name="valueConvert" id="valueConvert" size="15"></td>
</tr>

<tr>
    <td>Convert to:</td>
    <td><select name="convertType" id="convertType" size="1">
               <option disabled> Select a measurement type</option>
               <option value="celsius">Celsius</option>
               <option value="fahrenheit">Fahrenheit</option>
        </select>
    </td>
</tr>

<tr>
    <td><input type="submit" name="btnConvert" id="btnConvert" value="Convert"></td>
    <td><input type="reset" name="btnReset" id="btnReset" value="Reset"></td>
</tr>



</form>

<?php
 function tempConvert($value, $type){
    if($type== "fahrenheit"){
       return (((9/5)*$value) +(32));
   }
    elseif ($type== "celsius"){
       return (($valueConvert - 32) * (9/5));
   }
}

if (isset($_POST['btnConvert'])) { 
$valueConvert = $_POST['valueConvert'];
$convertType = $_POST['convertType'];

echo "The initial temperature was $valueConvert. The new temperature is tempConvert($valueConvert, $convertType).";
}
?>

    </body>
</html>

温度转换PHP

2 个答案: