angularjs中的多个查询字符串参数

Question

我在路线中传递和阅读多个查询字符串参数时苦苦挣扎。

$routeProvider.when("/joboffers:keywords:location", {
    controller: "jobOffersController",
    templateUrl: "/App/Views/JobOffer/All.html"
});

这是搜索页面：

$scope.searchJobOffer = function () {
    var vm = $scope.jobOfferSearchViewModel;
    var path = "/joboffers?keywords=" +( vm.keywords || "") + "&location=" + (vm.location || "");
    $location.path(path);
}

这是JobOffersController：

'use strict';
app.controller('jobOffersController', ['$scope', '$routeParams', 'jobOfferService', function ($scope, $routeParams, jobOfferService) {
    $scope.jobOffers = [];

    function init() {
        var keywords = $routeParams.keywords;
        var location = $routeParams.location;
    }

    init();
}]);

读取$ routeParams根本不起作用。如果我通过＆＃34;开发人员＆＃34;作为关键词和＆＃34;纽约＆＃34;作为位置，$ routeParam对象如下所示：

{keywords: "?keywords=developer&location=New Yor", location: "k"}

有人可以告诉我我做错了什么吗？提前谢谢。

P.S。 是否可能是因为错误配置的路由？ 当我通过searchJobOffer函数进行导航时，它会将URL编码为：http://localhost:49380/#/joboffers%3Fkeywords=developer&location=london，如果我尝试使用此网址http://localhost:49380/#/joboffers?keywords=developer&location=london，则路由系统会将我转到默认路由（＃/家）

Answer 1

$ routeProvider与查询字符串不匹配，只与路由匹配。此外，您要将完整url设置为$ location.path（），$ location.path（）仅获取网址的path部分。要设置包含查询字符串的整个网址，您需要使用$location.url()。

以下是一些选项：

1。使用漂亮的网址

$routeProvider.when("/joboffers/:location/:keywords", {
  controller: "jobOffersController",
  templateUrl: "/App/Views/JobOffer/All.html"
});

$scope.searchJobOffer = function () {
  var vm = $scope.jobOfferSearchViewModel;
  var path = "/joboffers/" + (vm.location || "") + "/" + ( vm.keywords || "");
  $location.path(path);
};

app.controller('jobOffersController', ['$scope', '$routeParams', 'jobOfferService', function ($scope, $routeParams, jobOfferService) {
  $scope.jobOffers = [];

  function init() {
    var keywords = $routeParams.keywords;
    var location = $routeParams.location;
  }

  init();
}]);

2。只匹配作业提供路径并从$ location.search（）

中提取参数

（请注意使用$location.url()代替$location.path()）

$routeProvider.when("/joboffers", {
  controller: "jobOffersController",
  templateUrl: "/App/Views/JobOffer/All.html"
});

$scope.searchJobOffer = function () {
  var vm = $scope.jobOfferSearchViewModel;
  var url = "/joboffers?keywords=" +( vm.keywords || "") + "&location=" + (vm.location || "");
  $location.url(url);
};

app.controller('jobOffersController', ['$scope', '$location', 'jobOfferService', function ($scope, $location, jobOfferService) {
  $scope.jobOffers = [];

  function init() {
    var search = $location.search();
    var keywords = search.keywords;
    var location = search.location;
  }

  init();
}]);

3。如果您需要匹配路由和查询字符串，请尝试更健壮的内容，例如angular-ui-router

$stateProvider.state("JobOffers", {
  url: '/joboffers?keywords&location',
  controller: "jobOffersController",
  templateUrl: "/App/Views/JobOffer/All.html"
});

$scope.searchJobOffer = function () {
  var vm = $scope.jobOfferSearchViewModel;
  var url = "/joboffers?keywords=" +( vm.keywords || "") + "&location=" + (vm.location || "");
  $location.url(url);
};

app.controller('jobOffersController', ['$scope', '$stateParams', 'jobOfferService', function ($scope, $stateParams, jobOfferService) {
  $scope.jobOffers = [];

  function init() {
    var keywords = $stateParams.keywords;
    var location = $stateParams.location;
  }

  init();
}]);