Question

if(sqlite3_open([databasePath UTF8String], & database) == SQLITE_OK) {
    NSLog(@"DB OPENED");
    // Setup the SQL Statement and compile it for faster access
    const char *sqlStatement ="select name from Medicine";

    sqlite3_stmt *compiledStatement;

    int result = sqlite3_prepare_v2(database, sqlStatement, -1, &compiledStatement, nil); 
    NSLog(@"RESULT %d", result);

    if(result == SQLITE_OK) {
        NSLog(@"RESULT IS OK...");

        // Loop through the results and add them to the feeds array
        while(sqlite3_step(compiledStatement) == SQLITE_ROW) {
            // Read the data from the result row
            NSLog(@"WHILE IS OK");

            **araci = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 1)];**

            NSLog(@"Data read");


            NSLog(@"wow: %",araci);


        }//while 
    }//if sqlite_prepare v2
    // Release the compiled statement from memory
    sqlite3_finalize(compiledStatement);
    NSLog(@"compiled stmnt finalized..");
}
sqlite3_close(database);
NSLog(@"MA_DB CLOSED");

问题

1）在大胆的代码之前一切都好。当我运行应用程序时，会在下面抛出异常。我的db中有一个表和一行相对，id（整数），name（varchar），desc（varchar）（我使用SQLite Manager创建了我的表）。

2-）SQLite Manager中的文本类型是什么？那是NSString吗？另外，我如何将字符串值（在表中）放入NSMutableArray？（我真的很难转换。）

*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** +[NSString stringWithUTF8String:]: NULL cString'

Answer 1

处理数据库返回的null，您可以使用以下代码来解决它


char *localityChars =  (char *)sqlite3_column_text(init_statement, 12);

if (localityChars ==null)
     self.Locality = nil;
else
     self.Locality = [NSString stringWithUTF8String: localityChars];

Answer 2

当列为NULL时，

sqlite3_column_text将返回空指针。你需要检查一下。

sql语句sqlite3_column_text有什么问题？

问题

2 个答案: