Question

Android代码：

public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {
    // TODO Auto-generated method stub

        View rootView;

        rootView = inflater.inflate(R.layout.view_contact_list, container, false);

        listview = (ListView) rootView.findViewById(R.id.listView1);

        Log.d("Contact List", "Before read method");

        ReadContacts();

        Log.d("Contact List", "After Read Method");

        Log.d("Before ", "Before Adapter Initialization");

        adapter = new ContactListAdapter(getActivity(), contact_list);

        Log.d("After",
                "After Adapter Initializaiton and before listview set adapter");

        listview.setAdapter(adapter);

        listview.setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> arg0, View arg1,
                    int arg2, long arg3) {
                // TODO Auto-generated method stub

                TextView name = (TextView) arg1
                        .findViewById(R.id.tvContactName);
                TextView phone = (TextView) arg1
                        .findViewById(R.id.tvContactPhone);

                Toast.makeText(
                        getActivity(),
                        "Name : " + name.getText().toString() + "Phone : "
                                + phone.getText().toString(),
                        Toast.LENGTH_SHORT).show();

            }
        });
        return rootView;

}

适配器工作正常，我可以在列表视图中看到数据，但我无法点击列表项。没有回应

我设置了android：clickable =“true”

片段是视图寻呼机的一部分

我不能使用列表片段并想使用适配器..错误是什么？

我还在onActivityCreated（）中粘贴了这个setonitemclick方法..它没有工作

列表视图的XML：

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical" >


<ListView
    android:id="@+id/listView1"
    android:layout_width="match_parent"
    android:layout_height="wrap_content"
    android:clickable="true"
    android:focusable="false"
     >
</ListView>

</LinearLayout>

我正在使用的适配器：

package com.example.eh;

import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;

import android.app.Activity;
import android.content.Context;
import android.view.View;
import android.view.ViewGroup;
import android.webkit.WebView.FindListener;
import android.widget.ArrayAdapter;
import android.widget.BaseAdapter;
import android.widget.Button;
import android.widget.TextView;

  public class ContactListAdapter extends BaseAdapter
 {


 Context context;
 List<Tuple> contact_list=new ArrayList<Tuple>();



public ContactListAdapter(Context ctx, List<Tuple> data)
{
    context = ctx;
    contact_list = data;
}

@Override
public int getCount() {
    // TODO Auto-generated method stub
    //return contacts.size();
    return contact_list.size();

}

@Override
public Object getItem(int arg0) {
    // TODO Auto-generated method stub
    return contact_list.get(arg0);
}

@Override
public long getItemId(int arg0) {
    // TODO Auto-generated method stub
    return 0;
}

public String getName(int arg0)
{
    return contact_list.get(arg0).getContactName();
}

public String getPhone(int arg0)
{
    return contact_list.get(arg0).getContactPhone();

}


@Override
public View getView(int position, View convertView, ViewGroup parent) {

    View view = convertView;
    ViewHolder holder = null;

    if (convertView == null) {

        view = ((Activity) context).getLayoutInflater().inflate(R.layout.row_full_contact_list, parent, false);
        holder = new ViewHolder(view);
        view.setTag(holder);

    } else {
        holder = (ViewHolder) view.getTag();
    }

    holder.name.setText(getName(position));
    holder.phone.setText(getPhone(position));

    return view;
}

private class ViewHolder {
    public TextView name;
    public TextView phone;
    public Button invite;

    public ViewHolder(View v)
    {
        name = (TextView) v.findViewById(R.id.tvContactName);
        phone = (TextView) v.findViewById(R.id.tvContactPhone);
        invite = (Button) v.findViewById(R.id.bInviteFriends);
    }

  }

 }

行项的XML：

 <?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:orientation="vertical" >

<RelativeLayout
    android:id="@+id/LeftSide"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content" >

    <TextView
        android:id="@+id/tvContactName"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:text="TextView"
        android:textSize="30dp"
        android:maxLines="1"         

        />

    <TextView
        android:id="@+id/tvContactPhone"
        android:layout_width="wrap_content"
        android:layout_height="wrap_content"
        android:layout_below="@id/tvContactName"
        android:text="TextView" />
</RelativeLayout>

<Button
    android:id="@+id/bInviteFriends"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:layout_alignParentRight="true"
    android:text="Invite" />

 </RelativeLayout>

Answer 1

您是否在breakpoint方法中添加onItemClick以确保其未被解雇？

尝试在listview's XML上添加以下代码：

android:focusable="false"

Answer 2

试试这个

listview.setOnItemClickListener(new AdapterView.OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> parent, View view,
                                                int position, long id) {
            // TODO Auto-generated method stub

            Toast.makeText(
                    getActivity(),position.toString+" is the position you clicked!!",Toast.LENGTH_SHORT).show();
            TextView name = (TextView) arg1
                    .findViewById(R.id.tvContactName);
            TextView phone = (TextView) arg1
                    .findViewById(R.id.tvContactPhone);

            Toast.makeText(
                    getActivity(),
                    "Name : " + name.getText().toString() + "Phone : "
                            + phone.getText().toString(),
                    Toast.LENGTH_SHORT).show();

        }
    });

OnItemClickListener在Fragments中的ListView中不起作用

2 个答案: