我的问题是继续我所要求的链接。 Load Country/State/City
我已经扩展到从db加载我的下拉列表,我只需要在我的第一个下拉列表中连接onchange方法,第二,请参阅代码。感谢任何帮助。
附加最新代码:
<select id="country" onchange="getStateByCountryId()"></select> <br />
<select id="state"></select> <br />
$(document).ready(function() {
var options = {
type: "POST",
url: "SearchPage.aspx/LoadCountry",
data: "{}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(msg) {
var returnedArray = msg.d;
country = $("#country");
country.append('<option>Select a Country</option>');
for (i = 0; i < returnedArray.length; i++) {
country.append("<option value='" + returnedArray[i].Id + "'>" + returnedArray[i].Name + "</option>");
}
}
};
$.ajax(options);
});
function getStateByCountryId() {
$("#country").change(function()
{
var _selected = $("#country").val();
var options =
{
type: "POST",
url: "SearchPage.aspx/StateBy",
data: "{'countryId':'" + _selected + "'}",
contentType: "application/json; charset=utf-8",
dataType: "json",
success: function(msg) {
$('#state').empty();
var returnedArray = msg.d;
state = $("#state");
for (var i = 0; i < returnedArray.length; ++i) {
state.append("<option value='" + returnedArray[i].Id + "'>" + returnedArray[i].Name + "</option>");
}
}
};
$.ajax(options);
});
}
但不填充?我这样做的方式是你想怎么做?
感谢。
答案 0 :(得分:25)
$("#state").change(function(){
//on-change code goes in here.
//variable "this" references the state dropdown element
});
答案 1 :(得分:3)
$(this).parent("select").attr("id");