多对多关系:org.hibernate.MappingException:无法确定类型:java.util.Set

时间:2014-10-31 14:47:07

标签: java jpa many-to-many

我正在尝试根据此示例与JPA建立多对多的双向关系:http://www.mkyong.com/hibernate/hibernate-many-to-many-example-join-table-extra-column-annotation/

我得到了

  

org.hibernate.MappingException:无法确定类型:java.util.Set,在表:T_ITEM,对于列:[org.hibernate.mapping.Column(itemHikes)]

如果有人可以帮助我,请参阅以下源代码:

班级项目

@Entity
@Table(name="T_ITEM")
public class Item implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private Long id;
    private Set<ItemHike> itemHikes = new HashSet<ItemHike>(0);

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.item", cascade=CascadeType.ALL)
    public Set<ItemHike> getItemHikes() {
        return this.itemHikes;
    }

    public void setItemHikes(Set<ItemHike> itemHikes) {
        this.itemHikes = itemHikes;
    }
}

班级远足

@Entity
@Table(name="T_HIKE")
public class Hike implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private Long id;

    private List<ItemHike> itemHikes = new ArrayList<ItemHike>(0);

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.hike", cascade=CascadeType.ALL)
    public List<ItemHike> getItemHikes() {
        return this.itemHikes;
    }

    public void setItemHikes(List<ItemHike> itemHikes) {
        this.itemHikes = itemHikes;
    }
}

Class ItemHike

@Entity
@Table(name="T_ITEM_HIKE")
@AssociationOverrides({
    @AssociationOverride(name = "pk.item", 
        joinColumns = @JoinColumn(name = "iditem")),
    @AssociationOverride(name = "pk.hike", 
        joinColumns = @JoinColumn(name = "idlist")) })


public class ItemHike implements Serializable {
    private static final long serialVersionUID = 1L;

    @EmbeddedId
    private ItemHikePK pk;

    private int quantity;

    //bi-directional many-to-one association to THike

    @Transient
    public Item getItem() {
        return getPk().getItem();
    }

    public void setItem(Item item) {
        getPk().setItem(item);
    }


    @Transient
    public Hike getHike() {
        return getPk().getHike();
    }

    public void setHike(Hike hike) {
        getPk().setHike(hike);
    }

    public ItemHike() {
    }

    public ItemHikePK getPk() {
        return this.pk;
    }

    public void setPk(ItemHikePK pk) {
        this.pk = pk;
    }

    public int getQuantity() {
        return this.quantity;
    }

    public void setQuantity(int quantity) {
        this.quantity = quantity;
    }
}

Class ItemHikePk

@Embeddable
public class ItemHikePK implements Serializable {
    //default serial version id, required for serializable classes.
    private static final long serialVersionUID = 1L;

    private Item item;
    private Hike hike;

    @ManyToOne
    public Item getItem() {
        return item;
    }

    public void setItem(Item item) {
        this.item = item;
    }

    @ManyToOne
    public Hike getHike() {
        return hike;
    }

    public void setHike(Hike hike) {
        this.hike = hike;
    }
}

2 个答案:

答案 0 :(得分:5)

Here is a similiar question !

您在字段上设置@Anottations,在Getters上也是如此,这是错误的,您必须在字段上或在Getters方法上添加注释。

错误的方式:

@Entity
@Table(name="T_ITEM")
public class Item implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private Long id;
    private Set<ItemHike> itemHikes = new HashSet<ItemHike>(0);

    @OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.item", cascade=CascadeType.ALL)
    public Set<ItemHike> getItemHikes() {
        return this.itemHikes;
    }

    public void setItemHikes(Set<ItemHike> itemHikes) {
        this.itemHikes = itemHikes;
    }
}

正确:

@Entity
@Table(name="T_ITEM")
public class Item implements Serializable {
    private static final long serialVersionUID = 1L;

    @Id
    private Long id;
    @OneToMany(fetch = FetchType.LAZY, mappedBy = "pk.item", cascade=CascadeType.ALL)
    private Set<ItemHike> itemHikes = new HashSet<ItemHike>(0);

    public Set<ItemHike> getItemHikes() {
        return this.itemHikes;
    }

    public void setItemHikes(Set<ItemHike> itemHikes) {
        this.itemHikes = itemHikes;
    }
}

答案 1 :(得分:2)

尝试将@OneToMany注释从getItemHikes()移至itemHikes字段。如果您希望注释有时在字段上,有时在getter上,则需要使用@Access注释。如果你不使用它,所有注释都需要在字段上或在getter上,而不是两者的混合。