Question

我不是在找人给我解决方案。我只是寻求一些帮助，为什么这不起作用。这也与其他可用的密码强度问题略有不同

def password(pwd):
        if len(pwd) >= 10:
            is_num = False
            is_low = False
            is_up = False
            for ch in pwd:
                if ch.isdigit():
                    is_num = True
                if ch.islower():
                    is_low = True
                if ch.isupper():
                    is_up = True

if __name__ == '__main__':
    #These "asserts" using only for self-checking and not necessary for auto-testing
    assert password(u'A1213pokl') == False, "1st example"
    assert password(u'bAse730onE4') == True, "2nd example"
    assert password(u'asasasasasasasaas') == False, "3rd example"
    assert password(u'QWERTYqwerty') == False, "4th example"
    assert password(u'123456123456') == False, "5th example"
    assert password(u'QwErTy911poqqqq') == True, "6th example"

Answer 1

你缺少2个返回语句来完成这项工作：

def password(pwd):
    if len(pwd) >= 10:
        is_num = False
        is_low = False
        is_up = False
        for ch in pwd:
            if ch.isdigit():
                is_num = True
            if ch.islower():
                is_low = True
            if ch.isupper():
                is_up = True
        return is_num and is_low and is_up
    return False

Answer 2

    def password(pwd):
        upper = any(ch.isupper() for ch in pwd)
        lower = any(ch.islower() for ch in pwd)
        is_dig = any(ch.isdigit() for ch in pwd)
        return  upper and lower and is_dig and len(pwd) > 10

检查密码的强度

2 个答案: