Question

我编写了一个查询来使用foreach检索不同的xml节点值我正在尝试从XML中检索不同的 BankName 和 TemplateModel 任何人都可以用更好的方式用ienumerable或类似的东西来编写查询我的Xml如下

<Bank>
<BankName BankName="DohaBank" TemplateModel="CT1">   
  <ChqBasics>      
  </ChqBasics>
  <XandYPosition>       
  </XandYPosition>
</BankName>
<BankName BankName="DohaBank" TemplateModel="CT2">   
  <ChqBasics>       
  </ChqBasics>
  <XandYPosition>        
  </XandYPosition>    
</BankName>  
<BankName BankName="IBQ" TemplateModel="CT1New">
    <ChqBasics>     
  </ChqBasics>
  <XandYPosition>     
  </XandYPosition>
</BankName>

我的c＃代码

 public List<string> bankload()
    {
        List<string> bankname=new List<string>();
        XDocument doc = XDocument.Load("newtest.xml");
       var result= (from item in doc.Descendants("BankName")
                select (string)item.Attribute("BankName")).Distinct();
       foreach (var item in result)
       {
           bankname.Add(item.ToString());
       }
        return bankname;
    }

    public static List<string> templateload(string bankname)
    {
        List<string> templatename = new List<string>();
        XDocument doc = XDocument.Load("newtest.xml");
        var result = (from item in doc.Descendants("BankName")
                      where item.Attribute("BankName").Value == bankname
                      select (string)item.Attribute("TemplateModel")).Distinct();
        foreach (var item in result)
        {
            templatename.Add(item.ToString());
        }
        return templatename;
    }

我需要将结果绑定到组合框

Answer 1

为什么不这样做？

public List<string> bankload()
{
    return
    (
        from item in XDocument.Load("newtest.xml").Descendants("BankName")
        select (string)item.Attribute("BankName")
    )
        .Distinct()
        .ToList();
}

public static List<string> templateload(string bankname)
{
    return
    (
        from item in XDocument.Load("newtest.xml").Descendants("BankName")
        where item.Attribute("BankName").Value == bankname
        select (string)item.Attribute("TemplateModel")
    )
        .Distinct()
        .ToList();
}

你是说像这样的lambdas吗？

public List<string> bankload()
{
    return
        XDocument
            .Load("newtest.xml")
            .Descendants("BankName")
            .Select(item => (string)item.Attribute("BankName"))
            .Distinct()
            .ToList();
}

public static List<string> templateload(string bankname)
{
    return
        XDocument
            .Load("newtest.xml")
            .Descendants("BankName")
            .Where(item => item.Attribute("BankName").Value == bankname)
            .Select(item => (string)item.Attribute("TemplateModel"))
            .Distinct()
            .ToList();
}

Answer 2

在XML中返回不同BankName / TemplateModel组合的列表：

var result = doc.Descendants("BankName")
                .Select(bn => new
                              {
                                 BankName = bn.Attribute("BankName").Value,
                                 TemplateModel = bn.Attribute("TemplateModel")
                                                   .Value
                              });

如何从xml中检索唯一值

2 个答案: