这个问题很容易修复客户端。但是为了性能,我想直接将它做到数据库。
LIST a
+------+-------+-------+
| name | score | cre |
+------+-------+-------+
| Abe | 3 | 1 |
| Zoe | 5 | 2 |
| Mye | 1 | 3 |
| Joe | 3 | 4 |
想要检索已连接的混合结果而无需重复。
Zoe (1st highest score)
Joe (1st last submitted)
Abe (2nd highest score)
Mye (2nd last submitted)
...
Clientside我自己进行每次搜索并逐步完成。 但在100.000+上它变得尴尬。能够使用LIMIT功能可以减轻很多事情!
SELECT name FROM a ORDER BY score DESC, cre DESC;
SELECT name FROM a ORDER BY cre DESC, score DESC;
答案 0 :(得分:1)
MySQL不提供像ROW_NUMBER
这样的分析函数。
实现这一目标的一种方法是将两个Order By
不同的查询连接在一起:
Select s.name, s.score_num, c.cre_num
From
(
Select name, @score_num := @score_num + 1 As score_num
From your_table, ( SELECT @score_num := 0 ) v
Order By score Desc
) s
Join
(
Select name, @cre_num := @cre_num + 1 As cre_num
From your_table, ( SELECT @cre_num := 0 ) v
Order By cre Desc
) c
On ( c.name = s.name )
返回
name score_num cre_num
Joe 3 1
Mye 4 2
Zoe 1 3
Abe 2 4
这是你想要的吗?