Question

我在数组中有 3个元素，其中包含字符串和数字（作为字符串）

例如，数组包含

等元素

 var elementArray:NSArray //"3","2","1","abc"

排序后变为

var sortedArray = //"1","2","3","abc"

我想首先创建一个字符串，最后创建数字。

预期输出应为

var sortedArray = //"abc","1","2","3"

如何交换数组元素。

请注意，如果数组有多个字符串和数字（"1"，"2"等字符串）。字符串（单词或字符）应该是第一个，数字（应该按升序排列）是最后的。

到目前为止，我试过这个。

 var sortedArray:NSArray = array.sortedArrayUsingComparator({(item1:AnyObject!, item2:AnyObject!) -> NSComparisonResult in
            let comparisonOptions:NSStringCompareOptions =
            NSStringCompareOptions.CaseInsensitiveSearch |
                NSStringCompareOptions.NumericSearch |
                NSStringCompareOptions.WidthInsensitiveSearch |
                NSStringCompareOptions.ForcedOrderingSearch;

            var str1:String = (item1 as String)
            var str2:String = (item2 as String)

            return str1.compare(str2, options: comparisonOptions, range: str1.startIndex ..< str1.endIndex, locale: NSLocale.currentLocale())
        })

将结果返回为"1","2","3","abc"。

但预期输出应为"abc","1","2","3"。我怎样才能在数组中交换对象。

Answer 1

var elementArray = ["1","2","3","abc","def"]
sort(&elementArray){
    if $0.toInt() != nil && $1.toInt() != nil{
        return $0 < $1
    }
    else if $0.toInt() == nil && $1.toInt() == nil{
        return $0 < $1
    }
    else
    {
        return $0 > $1
    }
}

这应该是有效的结果是＆＃34; ABC＆＃34; ＆＃34; DEF＆＃34; ＆＃34; 1＆＃34; ＆＃34; 2＆＃34; ＆＃34; 3＆＃34;

如果结果abc 3 2 1正常，请使用此

var elementArray = ["1","2","3","abc","def"]
    sort(&elementArray,>)

这个结果是＆＃34; def＆＃34; ＆＃34; ABC＆＃34; ＆＃34; 3＆＃34; ＆＃34; 2＆＃34; ＆＃34; 1＆＃34;

更新

var elementArray:NSArray = ["1","2","3","abc","def"]
var sortedArray:NSArray = elementArray.sortedArrayUsingComparator({(item1:AnyObject!, item2:AnyObject!) -> NSComparisonResult in
    let comparisonOptions:NSStringCompareOptions =
    NSStringCompareOptions.CaseInsensitiveSearch |
        NSStringCompareOptions.NumericSearch |
        NSStringCompareOptions.WidthInsensitiveSearch |
        NSStringCompareOptions.ForcedOrderingSearch;

    var str1:String = (item1 as String)
    var str2:String = (item2 as String)
    if str1.toInt() != nil && str2.toInt() != nil{
        return str1.compare(str2, options: comparisonOptions, range: str1.startIndex ..< str1.endIndex, locale: NSLocale.currentLocale())
    }
    else if str1.toInt() == nil && str2.toInt() == nil{
        return str1.compare(str2, options: comparisonOptions, range: str1.startIndex ..< str1.endIndex, locale: NSLocale.currentLocale())
    }
    else
    {
        return str2.compare(str1, options: comparisonOptions, range: str1.startIndex ..< str1.endIndex, locale: NSLocale.currentLocale())
    }
})

Answer 2

这是一种向Swift数组添加交换功能的方法：

public extension Array {
    mutating func swap(ind1: Int, _ ind2: Int){
        var temp: Element
        temp = self[ind1]
        self[ind1] = self[ind2]
        self[ind2] = temp
    }
}

现在，您可以按照以下方式使用：

let myArray = [[1], 2, "3"]
myArray.swap(0,2) // ["3", 2, [1]]

在Swift中交换数组值

2 个答案: