Question

忍受我，我还是C ++的新手......

所以我的困境是我有两个游戏的菜单，都在他们各自的开关声明/案例中。代码有效，但一旦完成，它就会关闭游戏。我不能为我的生活弄清楚如何循环回到我再次选择游戏的主菜单。

我的代码如下：

#include<iostream>
#include<string>
#include<cstdlib>
#include<ctime>
#include<iomanip>

using namespace std;

int main()
{
  string name;
  int choice; //the choices for the menu
  char sym; //part of the menu
  int number = rand() % 10 + 1; //sets number to a random number between 1-10
  int digit; // part of the math game
  bool menu = true;
  int guessNum; //number that user guesses
  int i; //loop variable
  bool guessRight = false;
  char answer = 'y';



  /questions omitted
  while (menu){ //start of loop and will come back here after each game finishes
    cout << setfill(sym) << setw(55);
    cout << "\n";
    cout << "\t Welcome," << ' ' << name << endl;
    cout << "Please choose a number from the following options:" << endl; //Gives the user the options to input using numbers.
    cout << "\n";
    cout << "\t1. Play the math game!" << endl;
    cout << "\t2. Play the guessing game!" << endl;
    cout << "\t3. Exit" << endl;
    cout << setfill(sym) << setw(55);
    cout << "\n";
    cin >> choice; //The user gets to input numbers 1-3 at this point

    switch (choice)
    {
      case 1:
        //Math game here
        break;

      case 2:
        //random number game here
        break;

      case 3: //exits the program
        cout << "I guess we're done here." << endl;
        return 0;
    }
  }
}

我自己省略了游戏，但我很困惑如何在游戏结束后从两个游戏循环回主菜单。一旦完成，我将提示用户“返回菜单？y / n”。我怀疑我必须插入一个do-while循环，但我不知道如何去做。我很感激任何建议！

Answer 1

代码完全符合您的要求！它要求用户提供一个选项，然后，除了给出选项3，返回到菜单的开头。

这是因为你有：

bool menu = true;
while (menu) {
   // your print and games
   // no modification of 'menu'
}

另请注意：

cout << setfill(sym) << setw(55);  // 'sym' is NOT initialized here.

如何在c ++中使用switch语句进行循环？

1 个答案: