Question

这是问题，我有一个类，我想在python中定义，以便能够将buck传递给另一个类，以便在调用主类的函数时说话。例如：

class Multi_Interface:
    def __init__(self):
        interfaces = [Interface("message A"), Interface("Message B")]
        self.set_interface(0)

    def set_interface(self, interface_index = 0):
        current_interface = self.interfaces[interface_index]
    # @todo: override the .operator to call the member of the current interface.

class Interface:
    def __init__(self, message):
        self.msg = message

    def do_stuff(self, message="I am a parameter"):
        print message + self.msg

mi = Multi_Interface()
mi.do_stuff(message="the internal message is: ")
mi.set_interface(1)
mi.do_stuff(message="the internal message is: ")
mi.do_stuff()

>>> the internal message is: mesage A
>>> the internal message is: mesage B
>>> I am a parameter: mesage B

有没有办法为类重载此运算符？怎么会超载这个运算符？我知道如何从子对象获取方法，前提是我可以在方法中获取字符串。

Answer 1

最终解决方案如下

class Multi_Interface:
    def __init__(self):
        self.interfaces = [Interface("message A"), Interface("Message B")]
        self.current_interface = None
        self.set_interface(0)

    def set_interface(self, interface_index = 0):
        self.current_interface = self.interfaces[interface_index]

    def __getattr__(self, name):
        return getattr(self.current_interface, name)

class Interface:
    def __init__(self, message):
        self.msg = message

    def do_stuff(self, message="I am a parameter "):
        print message + self.msg

mi = Multi_Interface()
mi.do_stuff(message="the internal message is: ")
mi.set_interface(1)
mi.do_stuff(message="the internal message is: ")
mi.do_stuff()

有没有办法重新定义的行为。 python类的运算符？

1 个答案: