Question

假设我有一张树的图像，当我点击屏幕时，它会变成汽车的图像，我该怎么做？这是我到目前为止的代码，但它不起作用。 （我有三张图片名为＆＃34; gp1＆＃34;，＆＃34; gp2＆＃34;和＆＃34; gp3＆＃34;所有这些图片都有不同数量的点按来更改图片。）

我在Spritekit中并使用Swift。

class GameScene: SKScene, SKPhysicsContactDelegate {

  //Create Touch
  createTouch()

}


override func didMoveToView(view: SKView) {

  func createTouch() {

    gestureRecognizer.numberOfTapsRequired = 1
    gestureRecognizer2.numberOfTapsRequired = 2
    gestureRecognizer3.numberOfTapsRequired = 3

    gestureRecognizer == UITapGestureRecognizer(target: self, action: "gp2")
    gestureRecognizer2 == UITapGestureRecognizer(target: self, action: "gp3")
    gestureRecognizer3 == UITapGestureRecognizer(target: self, action: "gp1")

  }

}

Answer 1

正如Mundi所说，对于每个UIImageView，请确保userInteractionEnabled = true。否则，用户无法点击图像。然后，创建gestureRecognizer。将操作设置为将处理手势的方法。接下来，将gestureRecognizer添加到UIImageView。最后，编写处理手势的方法。

@IBOutlet var gp1: UIImageView!
@IBOutlet var gp2: UIImageView!
@IBOutlet var gp3: UIImageView!

func createTouch() {
    // maker sure userInteractionEnabled is true
    gp1.userInteractionEnabled = true;
    gp2.userInteractionEnabled = true;
    gp3.userInteractionEnabled = true;

    // create the gesture recognizers
    let gestureRecognizer1 = UITapGestureRecognizer(target: self, action: "tapGesture:")
    let gestureRecognizer2 = UITapGestureRecognizer(target: self, action: "tapGesture:")
    let gestureRecognizer3 = UITapGestureRecognizer(target: self, action: "tapGesture:")

    // set the number of taps
    gestureRecognizer1.numberOfTapsRequired = 1
    gestureRecognizer2.numberOfTapsRequired = 2
    gestureRecognizer3.numberOfTapsRequired = 3

    // add the gesture recognizer to the UIImageViews
    gp1.addGestureRecognizer(gestureRecognizer1)
    gp2.addGestureRecognizer(gestureRecognizer2)
    gp3.addGestureRecognizer(gestureRecognizer3)
}

由于这些都是轻击手势，我决定使用一种方法和一种开关语句。但是，如果您愿意，可以为每个手势创建不同的方法。

func tapGesture(gesture: UITapGestureRecognizer) {
    switch gesture.numberOfTapsRequired {
    case 1:
        gp1.image = UIImage(named: "car")
    case 2:
        gp2.image = UIImage(named: "car")
    case 3:
        gp3.image = UIImage(named: "car")
    default:
        break
    }
}

Answer 2

您需要将识别器添加到视图中并实现操作处理程序gp2等。

对于UIImageView，您还应确保将userInteractionEnabled设置为true。

如何在Swift中的应用程序中实现UIGestureRecognizer？

2 个答案: