Question

创建AWS SNS主题时：

a = conn.create_topic(topicname)

或者已经创建了主题：

a = conn.get_all_topics()

结果是：

{u'CreateTopicResponse': {u'ResponseMetadata': {u'RequestId': u'42b46710-degf-52e6-7d86-2ahc8e1c738c'}, u'CreateTopicResult': {u'TopicArn': u'arn:aws:sns:eu-west-1:467741034465:exampletopic'}}}

问题是如何将主题的ARN作为字符串：arn:aws:sns:eu-west-1:467741034465:exampletopic？

Answer 1

import boto

def get_account_id():
    # suggested by https://groups.google.com/forum/#!topic/boto-users/QhASXlNBm40
    return boto.connect_iam().get_user().arn.split(':')[4]

def topic_arn_from_name(self, region, name):
    return ":".join(["arn", "aws", "sns", region, get_account_id(), name])

Answer 2

当您创建新主题时，boto将返回包含您在上面描述的数据的Python字典。要将主题ARN作为字符串，只需在字典中引用该键，如下所示：

a = conn.create_topic(topicname)
a_arn = a['CreateTopicResponse']['CreateTopicResult']['TopicArn']

它有点笨重，但它有效。

list_topics调用返回不同的结构，基本上是这样的：

{u'ListTopicsResponse':
  {u'ListTopicsResult':
    {u'NextToken': None,
     u'Topics': [
      {u'TopicArn': u'arn:aws:sns:us-east-1:467741034465:exampletopic'},
      {u'TopicArn': u'arn:aws:sns:us-east-1:467741034465:footopic'}
     ]
    },
  u'ResponseMetadata': {u'RequestId': u'aef821f6-d595-55e1-af14-6d3a8064536a'}}}

在这种情况下，如果您想获得第一个主题的ARN，您将使用：

a = conn.list_topics()
a_arn = a['ListTopicsResponse']['ListTopicsResult']['Topics'][0]['TopicArn']

Boto - AWS SNS如何提取主题的ARN号码

2 个答案: