Question

我有两个表，我的外部选择聚合所有那些存在于我放在where子句中的另一个表中的id。两个表都是使用通配符函数生成的。以下是查询 -

SELECT count(id), timestamp  FROM (TABLE_QUERY(dataset1, 'expr'))  
WHERE id IN (SELECT id FROM (TABLE_QUERY(dataset1, 'expr')) 
WHERE timestamp < 1414670361836)  ) group by timestamp

我收到以下错误 -

查询失败错误：（L1：56）：JOIN（包括半连接）和UNION ALL （逗号）不能组合在一个SELECT语句中。要么搬家 UNION ALL为内部查询或JOIN为外部查询。

有人能指出我是什么问题，我该如何解决？

Answer 1

使用处理公共数据的查询重新措辞。

这不起作用：

SELECT COUNT(actor), created_at
FROM (TABLE_QUERY([publicdata:samples], "table_id CONTAINS 'github'"))
WHERE actor IN (
  SELECT actor
  FROM (TABLE_QUERY([publicdata:samples], "table_id CONTAINS 'github'"))
  WHERE created_at > '')  
GROUP BY created_at

Error: (L2:1): JOIN (including semi-join) and UNION ALL (comma) may not be combined in a single SELECT statement. Either move the UNION ALL to an inner query or the JOIN to an outer query.

这样做：

SELECT COUNT(actor), created_at
FROM (
  SELECT actor, created_at
  FROM (TABLE_QUERY([publicdata:samples], "table_id CONTAINS 'github'"))
)
WHERE actor IN (
  SELECT actor
  FROM (TABLE_QUERY([publicdata:samples], "table_id CONTAINS 'github'"))
  WHERE created_at > ''
  LIMIT 100)  
GROUP BY created_at

我刚刚移动了

  SELECT actor, created_at
  FROM (TABLE_QUERY([publicdata:samples], "table_id CONTAINS 'github'"))

到内部查询。

分组依据选择不起作用

1 个答案: