Question

我将三个人的数字放在一个arraylist中，如果三个人的数字相同，那么整体occurrences++;这是我的算法，但它不适合这种情况!!

5（第一人有5个人）
  13 20 22 43 146

4（第二人有4个num）
  13 22 43 146

5（第三人有5个num）
  13 43 67 89 146

int occurrences = 0;
for (int i = 0; i<n; ++i){
    for (int j = n; j<n+b; ++j ){
        if(arr.get(i)==arr.get(j)){
            System.out.println(arr.get(i)+" " +arr.get(j));
            for(int k=n+b; k<arr.size(); ++k){
                if(arr.get(j)==arr.get(k)){
                    ++occurrences;
                    System.out.println(arr.get(k));
                }
            }
        }
    }
}

Answer 1

如果您有3个3人阵列

，请尝试此操作

public static void main(String args[]) {
    Scanner sc = new Scanner(System.in);
    System.out.println("Enter numbers for 1st person seprated by ',' like 1,2,3....");
    String noForFirst = sc.nextLine();
    String[] a = noForFirst.split(",");
    System.out.println("Enter numbers for 2nd person seprated by ',' like 1,2,3....");
    String noForSecond = sc.nextLine();
    String[] b = noForSecond.split(",");
    System.out.println("Enter numbers for 3rd person seprated by ',' like 1,2,3....");
    String noForThird = sc.nextLine();
    String[] c = noForThird.split(",");
    int occurrences = 0;
    for (int i = 0; i < a.length; ++i) {
        for (int j = 0; j < b.length; ++j) {
            if (a[i].equals(b[j])) {
                for (int k = 0; k < c.length; ++k) {
                    if (a[i].equals(c[k])) {
                        ++occurrences;
                        System.out.println(a[i]);
                    }
                }
            }
        }
    }
    System.out.println("occurrences = " + occurrences);

<强>输入

Enter numbers for 1st person seprated by ',' like 1,2,3.... 1,5,9,7,6 Enter numbers for 2nd person seprated by ',' like 1,2,3.... 1,4,8,7,3,5 Enter numbers for 3rd person seprated by ',' like 1,2,3.... 1,7,2

<强>输出

1 7 occurrences = 2

检查三个数组是否具有相同的值

1 个答案: