Question

Version: postgreSQL 9.3

我已经写了以下程序：

CREATE OR REPLACE FUNCTION drop_if_exists(table_name name, schema_name name) RETURNS integer AS $$
BEGIN
    IF(SELECT EXISTS(
            SELECT * 
            FROM pg_class c
            JOIN pg_catalog.pg_namespace n ON n.oid = c.relnamespace
            WHERE relname = table_name AND
                nspname = schema_name
        ) as ex) = true
        THEN
            execute 'DROP TABLE ' || schema_name || '.' || table_name;
            RETURN 1;
        ELSE
            RETURN 0;
    END IF;
END
$$ LANGUAGE plpgsql;

DO $$
BEGIN
    drop_if_exists('ords', 'public'); --ERROR:  syntax error at or near drop_if_exists"
END
$$ LANGUAGE plpgsql;

该代码存在哪些问题？

Answer 1

缺少perform就是一个。没有检查其他错误。

perform drop_if_exists(...

为什么我不能在匿名的plpg块中执行一个函数？

1 个答案: