Question

我有以下文字：

Test 123:

This is a blue car

Test:

This car is not blue

This car is yellow

Hello:

This is not a test

我想整理一个正则表达式，找到所有以Test或Hello开头且以冒号开头的项目，以及可选的树数字编号，然后返回所有内容，直到符合相同描述的下一行。因此，对于上面的文本，findall正则表达式将返回一个数组：

[("Test", "123", "\nThis is a blue car\n"),
 ("Test", "", "\nThis car is not blue\n\nThis car is yellow\n"),
 ("Hello", "", "\nThis is not a test")]

到目前为止，我得到了这个：

r = re.findall(r'^(Test|Hello) *([^:]*):$', test, re.MULTILINE)

它根据描述匹配每一行，但我不确定如何捕获内容，直到下一行以冒号结束。有什么想法吗？

Answer 1

您可以使用以下使用DOTALL修饰符的正则表达式

(?:^|\n)(Test|Hello) *([^:]*):\n(.*?)(?=\n(?:Test|Hello)|$)

DEMO

>>> import re
>>> s = """Test 123:
... 
... This is a blue car
... 
... Test:
... 
... This car is not blue
... 
... This car is yellow
... 
... Hello:
... 
... This is not a test"""
>>> re.findall(r'(?s)(?:^|\n)(Test|Hello) *([^:]*):\n(.*?)(?=\n(?:Test|Hello)|$)', s)
[('Test', '123', '\nThis is a blue car\n'), ('Test', '', '\nThis car is not blue\n\nThis car is yellow\n'), ('Hello', '', '\nThis is not a test')]

Answer 2

import re
p = re.compile(ur'(Test|Hello)\s*([^:]*):\n(\n.*?)(?=Test[^:]*:|Hello[^:]*:|$)', re.DOTALL | re.IGNORECASE)
test_str = u"Test 123:\n\nThis is a blue car\n\nTest:\n\nThis car is not blue\n\nThis car is yellow\n\nHello:\n\nThis is not a test"

re.findall(p, test_str)

你可以尝试一下。参见演示。

http://regex101.com/r/eM1xP0/1

Python正则表达式搜索行以冒号结尾，所有文本以冒号结尾，直到下一行结尾

2 个答案: