Question

我需要从R中的以下数据框中为每个组[yearmonth]值选择前两个值。我已经按照count和yearmonth对数据进行了排序。如何在以下数据中实现这一点？

 yearmonth  name    count
1   201310  Dovas   5
2   201310  Indulgd 2
3   201310  Justina 1
4   201310  Jolita  1
5   201311  Shahrukh Sheikh 1
6   201311  Dovas   29
7   201311  Justina 13
8   201311  Lina    8
9   201312  sUPERED 7
10  201312  John Hansen 7
11  201312  Lina D. 6
12  201312  joanna1st   5

Answer 1

或使用来自@ jazzurro帖子的data.table（mydf）。一些选项是

  library(data.table)
  setDT(mydf)[order(yearmonth,-count), .SD[1:2], by=yearmonth]

或者

   setDT(mydf)[mydf[order(yearmonth, -count), .I[1:2], by=yearmonth]$V1,]

或者

   setorder(setkey(setDT(mydf), yearmonth), yearmonth, -count)[
                                          ,.SD[1:2], by=yearmonth]
  #    yearmonth        name count
  #1:    201310       Dovas     5
  #2:    201310     Indulgd     2
  #3:    201311       Dovas    29
  #4:    201311     Justina    13
  #5:    201312     sUPERED     7
  #6:    201312 John Hansen     7

Answer 2

这是一种方式：

library(dplyr)

mydf %>%
    group_by(yearmonth) %>%
    arrange(desc(count)) %>%
    slice(1:2)

#  yearmonth        name count
#1    201310       Dovas     5
#2    201310     Indulgd     2
#3    201311       Dovas    29
#4    201311     Justina    13
#5    201312     sUPERED     7
#6    201312 John Hansen     7

数据

mydf <- data.frame(yearmonth = rep(c("201310", "201311", "201312"), each = 4), name = c("Dovas", "Indulgd", "Justina", "Jolita", "Shahrukh Sheikh", "Dovas", "Justina", "Lina", "sUPERED", "John Hansen", "Lina D.", "joanna1st"), count = c(5,2,1,1,1,29,13,8,7,7,6,5), stringsAsFactors = FALSE)

Answer 3

使用base R你可以做类似的事情：

# sort the data, skip if already done
df <- df[order(df$yearmonth, df$count, decreasing = TRUE),]

然后，获得前两个元素：

df[ave(df$count, df$yearmonth, FUN = seq_along) <= 2, ]

使用R在列中的组中选择前N个值

3 个答案: