Ubound可以返回数组的最大索引值,但是在多维数组中,我如何指定WHICH维度我想要最大索引?
例如
Dim arr(1 to 4, 1 to 3) As Variant
在这个4x3阵列中,我如何获得Ubound返回4,以及如何将Ubound返回3?
答案 0 :(得分:49)
ubound(arr, 1)
和
ubound(arr, 2)
答案 1 :(得分:13)
您需要处理UBound
的可选 Rank 参数。
Dim arr(1 To 4, 1 To 3) As Variant
Debug.Print UBound(arr, 1) '◄ returns 4
Debug.Print UBound(arr, 2) '◄ returns 3
答案 2 :(得分:5)
[这是一个迟到的答案,解决了问题的标题(因为这是人们在搜索时会遇到的)而不是OP问题的具体内容已经得到了充分的回答]
Ubound
有点脆弱,因为它无法知道数组有多少维度。您可以使用错误捕获来确定数组的完整布局。以下内容返回一组数组,每个维度一个。 count
属性可用于确定维度的数量,并可根据需要提取其下限和上限:
Function Bounds(A As Variant) As Collection
Dim C As New Collection
Dim v As Variant, i As Long
On Error GoTo exit_function
i = 1
Do While True
v = Array(LBound(A, i), UBound(A, i))
C.Add v
i = i + 1
Loop
exit_function:
Set Bounds = C
End Function
像这样使用:
Sub test()
Dim i As Long
Dim A(1 To 10, 1 To 5, 4 To 10) As Integer
Dim B(1 To 5) As Variant
Dim C As Variant
Dim sizes As Collection
Set sizes = Bounds(A)
Debug.Print "A has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(B)
Debug.Print vbCrLf & "B has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
Set sizes = Bounds(C)
Debug.Print vbCrLf & "C has " & sizes.Count & " dimensions:"
For i = 1 To sizes.Count
Debug.Print sizes(i)(0) & " to " & sizes(i)(1)
Next i
End Sub
输出:
A has 3 dimensions:
1 to 10
1 to 5
4 to 10
B has 1 dimensions:
1 to 5
C has 0 dimensions:
答案 3 :(得分:0)
除了已经很好的答案之外,还要考虑这个函数来检索维度及其边界的数量,这与John's answer类似,但是看起来有点不同:
Function sizeOfArray(arr As Variant) As String
Dim str As String
Dim numDim As Integer
numDim = NumberOfArrayDimensions(arr)
str = "Array"
For i = 1 To numDim
str = str & "(" & LBound(arr, i) & " To " & UBound(arr, i)
If Not i = numDim Then
str = str & ", "
Else
str = str & ")"
End If
Next i
sizeOfArray = str
End Function
Private Function NumberOfArrayDimensions(arr As Variant) As Integer
' By Chip Pearson
' http://www.cpearson.com/excel/vbaarrays.htm
Dim Ndx As Integer
Dim Res As Integer
On Error Resume Next
' Loop, increasing the dimension index Ndx, until an error occurs.
' An error will occur when Ndx exceeds the number of dimension
' in the array. Return Ndx - 1.
Do
Ndx = Ndx + 1
Res = UBound(arr, Ndx)
Loop Until Err.Number <> 0
NumberOfArrayDimensions = Ndx - 1
End Function
使用示例:
Sub arrSizeTester()
Dim arr(1 To 2, 3 To 22, 2 To 9, 12 To 18) As Variant
Debug.Print sizeOfArray(arr())
End Sub
及其输出:
Array(1 To 2, 3 To 22, 2 To 9, 12 To 18)
答案 4 :(得分:0)
循环D3方式;
Sub SearchArray()
Dim arr(3, 2) As Variant
arr(0, 0) = "A"
arr(0, 1) = "1"
arr(0, 2) = "w"
arr(1, 0) = "B"
arr(1, 1) = "2"
arr(1, 2) = "x"
arr(2, 0) = "C"
arr(2, 1) = "3"
arr(2, 2) = "y"
arr(3, 0) = "D"
arr(3, 1) = "4"
arr(3, 2) = "z"
Debug.Print "Loop Dimension 1"
For i = 0 To UBound(arr, 1)
Debug.Print "arr(" & i & ", 0) is " & arr(i, 0)
Next i
Debug.Print ""
Debug.Print "Loop Dimension 2"
For j = 0 To UBound(arr, 2)
Debug.Print "arr(0, " & j & ") is " & arr(0, j)
Next j
Debug.Print ""
Debug.Print "Loop Dimension 1 and 2"
For i = 0 To UBound(arr, 1)
For j = 0 To UBound(arr, 2)
Debug.Print "arr(" & i & ", " & j & ") is " & arr(i, j)
Next j
Next i
Debug.Print ""
End Sub
答案 5 :(得分:0)
UBound(myArray, 1)
返回二维数组中的行数UBound(myArray, 2)
返回二维数组中的列数但是,让我们更进一步,假设您需要范围的最后一行和最后一列,它们已被写入二维数组。该行(或列)应转换为一维数组。例如。如果我们的二维数组看起来像这样:
然后运行下面的代码,会给你 2 个一维数组,即最后一列和最后一行:
Sub PrintMultidimensionalArrayExample()
Dim myRange As Range: Set myRange = Range("a1").CurrentRegion
Dim myArray As Variant: myArray = myRange
Dim lastRowArray As Variant: lastRowArray = GetRowFromMdArray(myArray, UBound(myArray, 1))
Dim lastColumnArray As Variant
lastColumnArray = GetColumnFromMdArray(myArray, UBound(myArray, 2))
End Sub
Function GetColumnFromMdArray(myArray As Variant, myCol As Long) As Variant
'returning a column from multidimensional array
'the returned array is 0-based, but the 0th element is Empty.
Dim i As Long
Dim result As Variant
Dim size As Long: size = UBound(myArray, 1)
ReDim result(size)
For i = LBound(myArray, 1) To UBound(myArray, 1)
result(i) = myArray(i, myCol)
Next
GetColumnFromMdArray = result
End Function
Function GetRowFromMdArray(myArray As Variant, myRow As Long) As Variant
'returning a row from multidimensional array
'the returned array is 0-based, but the 0th element is Empty.
Dim i As Long
Dim result As Variant
Dim size As Long: size = UBound(myArray, 2)
ReDim result(size)
For i = LBound(myArray, 2) To UBound(myArray, 2)
result(i) = myArray(myRow, i)
Next
GetRowFromMdArray = result
End Function