我无法弄清楚为什么我无法调用我的方法。我检查了几次并尝试运行它,但它总是在我输入一个值的钱后结束。它应该使用一百,五十,二十,几十,五,单身,四分之一,硬币,镍币和便士返回给定金额的变化金额。因此如果它是42.55美元,那么输出将是" 0 0 2 0 0 2 2 0 1 0" (两个二十几岁,两个单打,两个季度,一个镍)。提前谢谢!
import java.util.Scanner;
public class MakeChange {
public static void main(String arg[]) {
Scanner readmoney = new Scanner(System.in);
System.out.println("Money amount? >");
double money = readmoney.nextDouble();
System.out.println();
String thing = makeChange(money);
}
public static String makeChange(double money) {
int hundreds = (int) money/100;
int fifties = (int)(money/50) - (2*hundreds);
int twenties = (int) (money/20) - (5*hundreds) - (int)(2.5*fifties);
int tens = (int)(money/10) - (10*hundreds) - (5*fifties) - (2*twenties);
int fives = (int)(money/5) - (20*hundreds) - (10*fifties) - (4*twenties) - (2*tens);
int singles = (int)(money) - (100*hundreds) - (50*fifties) - (20*twenties) - (10*tens) - (5*fives);
int quarters = (int)(money/0.25) - (400*hundreds) - (200*fifties) - (80*twenties) - (40*tens) - (20*fives) - (4*singles);
int dimes = (int)(money/0.1) - (1000*hundreds) - (500*fifties) - (200*twenties) - (100*tens) - (50*fives) - (10*singles) - (int)(2.5*quarters);
int nickels = (int)(money/0.05) - (2000*hundreds) - (1000*fifties) - (400*twenties) - (200*tens) - (100*fives) - (20*singles) - (5*quarters) - (2*dimes);
int pennies = (int)(money/0.01) - (10000*hundreds) - (5000*fifties) - (2000*twenties) - (1000*tens) - (500*fives) - (100*singles) - (25*quarters) - (10*dimes) - (5*nickels);
String change = (hundreds + " " + fifties + " " + twenties + " " + tens + " " + fives + " " + singles + " " + quarters + " " + dimes + " " + nickels + " " + pennies);
return change;
} }
答案 0 :(得分:4)
String thing = makeChange(money);
}
// end of program
您不打印结果。
调用该方法(并且不会因异常而崩溃)。
答案 1 :(得分:0)
成功调用该方法。它返回一个结果,将其存储在变量中,然后程序结束。您需要实际将返回值打印到控制台以显示内容。
public static void main(String arg[]) {
Scanner readmoney = new Scanner(System.in);
System.out.println("Money amount? >");
double money = readmoney.nextDouble();
System.out.println();
String thing = makeChange(money);
System.out.println(thing);
}