Question

我试图用用户输入的三个单词作为首字母缩略词：

 import java.util.Scanner;
 public class Acronym
 {
    public static void main(String[] args)
    {    

       Scanner input = new Scanner(System.in);
       String phrase;
       System.out.println("Please, enter the three words here>> ");
       phrase = input.nextLine();     
       char first, second, third;
       int stringLength;
       int x = 0;
       char c;
       stringLength = phrase.length();
       first = phrase.charAt(0);
       second = phrase.charAt(x + 1);
       third = phrase.charAt(x + 1);

          for( x = 0; x < stringLength; x++);
          {
             int a = 1;
             c = phrase.charAt(x);

             if(Character.isWhitespace(c));
               if( a <= 1)
                second = phrase.charAt(x+1);

             else if(a <= 2)
                third = phrase.charAt(x++);
          }

      System.out.println("The acronym is " + first + second + third);
   }

 }

但是，每当我尝试输入StringIndexOutOfBoundExceptions时，都会显示错误。例如，我试图输入三个单词＆＃34; One Two Three＆＃34;这就是结果：

请输入单词/短语：一二三

线程中的异常＆＃34; main＆＃34; java.lang.StringIndexOutOfBoundsException：字符串索引超出范围：13 at java.lang.String.charAt（String.java:646） at Acronym.main（Acronym.java:23）

Answer 1

删除分号

for (x = 0; x < stringLength; x++);
                                  ^

正在终止for循环。对于终止if语句

的分号，也是如此

if (Character.isWhitespace(c));
                              ^

请使用大括号围绕控制块

显示StringIndexOutOfBoundExceptions错误

1 个答案: