Question

我有两个SQL选择。

首先：

SELECT v.red_club, count(v.red_club) 
FROM v_round as v
GROUP BY v.red_club

它正在返回：

red_club   count(v.red_club) 
ABC        22
DEF        12
XYZ        4

第二次选择：

SELECT v.green_club, count(v.green_club) 
FROM v_round as v
GROUP BY v.green_club

它正在返回：

green_club   count(v.green_club) 
ABC        5
DEF        9
XYZ        33

如何将计数加在一起（在一个选择中），以便结果如下：

club   count(total) 
ABC        27
DEF        21
XYZ        37

Answer 1

您是否尝试过UNION-ing每个查询的结果？

SELECT lbl, SUM(cnt)
FROM(
     SELECT v.red_club lbl, count(v.red_club)  cnt
     FROM v_round as v
     GROUP BY v.red_club
     UNION ALL
     SELECT v.green_club lbl, count(v.green_club) cnt
     FROM v_round as v
     GROUP BY v.green_club
)
Group by lbl

Answer 2

像这样的东西

    select red.red_club as club, rcount+gcount as cout 
from 
(
SELECT v.red_club, count(v.red_club) as rcount
FROM v_round as v
GROUP BY v.red_club
) as red 
inner join 
(
SELECT v.green_club, count(v.green_club) as gcount
FROM v_round as v
GROUP BY v.green_club
) as green on red.red_club = green.green_club

SQL连接两个计数选择

2 个答案: