Question

我正在寻找在SQL中提取如下所示数据的方法：

"Develop_Server   Linux15a1   /home   5152384   2136036   2754616      44"
"Homolog_Server   Linux37a9   /var   5152384   2136036   2754616      57"
"Produc_Server    Linux43a5   /usr   5152384   2136036   2754616      98"
"Produc_Server    Linux23a0   /sys   5152384   2136036   2754616      43"

select first field as Server, second field as Server_name, third field as FS,
fourth field as fs_width, fifth field as FS_Used, sisxth field as FS_available, 
seventh field as Perc_Usage
(Each row is a record)
Please help me.
Thanks.

Answer 1

看起来你的行是固定长度的。你可以这样做：

select substr(row, 1, 19) as Server,
       substr(row, 20, 10) as Server_name, 
       . . .

你需要弄清楚正确的长度和偏移是什么。

大多数数据库都支持substr()或substring()。

您可能还想删除空格。大多数数据库都支持trim()或rtrim()和ltrim()。

Answer 2

首先，创建目标表：

CREATE TABLE FinalTable
([Server] varchar(50), 
[Server_name] varchar(50), 
[FS] varchar(50), 
[fs_width] varchar(50), 
[FS_Used] varchar(50), 
[FS_available] varchar(50), 
[Perc_Usage] varchar(50))
;

逐行使用游标和动态sql

declare @sql varchar(max)
declare @onlyField varchar(max)

DECLARE db_cursor CURSOR FOR  
SELECT onlyField from logTable 

OPEN db_cursor   
FETCH NEXT FROM db_cursor INTO @onlyField   

WHILE @@FETCH_STATUS = 0   
BEGIN   
       SET @sql = 'insert into FinalTable select '''+REPLACE(@onlyField,'|',''',''')+''''

        EXEC (@sql)   

       FETCH NEXT FROM db_cursor INTO @onlyField   
END   

CLOSE db_cursor   
DEALLOCATE db_cursor

从记录中提取第N个字段

2 个答案: