Question

我想要做的是将网站的HTML存储在php变量中，以便在某种情况下回显它。我的PHP代码：

<?php
$url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$URL = "http://www.example.com/";
$URL2 = "http://www.example2.com/";
$website1 = ?
$website2 = ?
if($url == $URL) {
    echo $website1;
} else if($url == $URL2) {
    echo $website2;
}
?>

我希望将此HTML（下方）存储在$website1中还会在$website2

中存储HTML

<html>
    <head>
        <link rel='stylesheet' type='text/css' media='all' href='css/style.css'>
        <link rel='stylesheet' type='text/css' media='all' href='css/jquery-ui-1.10.4.custom.css'>
        <title>Website #One</title>
        <script type='text/javascript' src='js/jquery-1.9.1.js'></script>
        <script type='text/javascript' src='js/jquery-ui-1.10.4.custom.js'></script>
        <script type='text/javascript' src='js/script.js'></script>
    </head>
    <body>
    <div id='header'></div>
    <div id='menu'>
        <button id='navbtn' class='active btn'>Home</button><button id='navbtn2' class='btn'>Pictures</button><button id='navbtn3' class='btn'>Videos</button><button id='navbtn4' class='btn'>Games</button><button id='navbtn4' class='btn'>About</button><button id='navbtn5' class='btn'>Contact</button>
    </div>
    <div id='content'></div>




    </body>
</html>

我怎样才能实现这个目标？

Answer 1

我不了解您正在使用的逻辑，但您可以使用PHP的内置函数file_get_contents()来实现这一点。使用这种方式：

<?php
    $url = "http://".getenv("HTTP_HOST")."/".getenv("REQUEST_URI");
    $URL = "http://www.example.com/";
    $URL2 = "http://www.example2.com/";
    $website1 = file_get_contents($URL);
    $website2 = file_get_contents($URL2);
    if($url == $URL) {
        echo $website1;
    } else if($url == $URL2) {
        echo $website2;
    }
?>

Answer 2

您可以使用file_get_contents(); 或者CURL库 http://php.net/manual/fr/book.curl.php

Answer 3

Curl是一种很好的方法：http://www.digimantra.com/technology/php/get-data-from-a-url-using-curl-php/

<?php
$url='http://twitter.com/statuses/user_timeline/16387631.json'; //rss link for the twitter timeline
print_r(get_data($url)); //dumps the content, you can manipulate as you wish to

/* gets the data from a URL */

function get_data($url)
{
$ch = curl_init();
$timeout = 5;
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT,$timeout);
$data = curl_exec($ch);
curl_close($ch);
return $data;
}
?>

Answer 4

谢谢你们，我能够从你们的答案中学习并设法让它在这里工作是我最后的PHP代码：

<?php
$get_url = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$url1 = "http://thedag.ga/thedagga/main.php";
$url2 = "http://thedag.ga/zp/zp18.php";
$tdurl1 = "http://thedag.ga/";
$tdurl2 = "http://www.thedag.ga/";
$zpurl1 = "http://zp.thedag.ga/";
$zpurl2 = "http://zp18.thedag.ga/";
$zpurl3 = "http://zp4rker.thedag.ga/";
if($get_url == $tdurl1 || $get_url == $tdurl2) {
    print_r(file_get_contents($url1));
} else if($get_url == $zpurl1 || $get_url == $zpurl2 || $get_url == $zpurl3) {
    print_r(file_get_contents($url2));
}
?>

Answer 5

为什么不把两个版本放在自己的PHP文件中，也就是说，如果它只是一些简单的单页html，而不是整个网站，那么其他建议可能会更好。

<?php
$url = "http://".getenv("HTTP_HOST")."/".getenv("REQUEST_URI");
$URL = "http://www.example.com/";
$URL2 = "http://www.example2.com/";
if($url == $URL) {
    include 'header1.php';
} else if($url == $URL2) {
    include 'header2.php';
}
?>

如何在php变量中存储HTML

5 个答案: