Question

我在html中有以下代码

＆＃13;

<section>
    <section>
        <h2>Title1</h2>
        <p>Text1</p>
        <p>Text1</p>
     </section>
  <section>
        <h2>Title2</h2>
        <p>Text2</p>
        <p>Text2</p>
     </section>
  <section>
        <h2>Title3</h2>
        <p>Text3</p>
        <p>Text3</p>
     </section>
  </section>
<section>
        <h2>Title2-1</h2>
        <p>Text2-1</p>
        <p>Text2-1</p>
</section>
<section>
        <h2>Title3-1</h2>
        <p>Text3-1</p>
        <p>Text3-1</p>
</section>

＆＃13;

＆＃13; 因为在某些章节中有子章节而有些章节没有。我想抓住不具有小节的子节和节的内容我试图迭代子部分，以便我可以在scrapy中创建一个索引。我有以下scrapy代码：

class RUSpider(BaseSpider):
name = "ru"
allowed_domains = ["http://127.0.0.1:8000/"]
start_urls = [
    "http://127.0.0.1:8000/week2/1_am/#/",
    "http://127.0.0.1:8000/week1/1/",
    "http://127.0.0.1:8000/week3/1_am/"
]
rules = [
    Rule(SgmlLinkExtractor(), follow=True)
]

def parse(self, response):

    filename = response.url.split("/")[3]
    hxs = HtmlXPathSelector(response)
    divs = hxs.select('//div')
    sections = divs.select('//section').extract()
   # print sections.extract


 #class definition for scrapy and html selector

    for each in sections: #iterate over loop [above sections]
        soup = BeautifulSoup(each)
        sp= soup.prettify()
        elements = soup.findAll("section".split())
        print len(elements),'sublength'
        if len(elements ) > 1:
            for element in elements:
                for subelement in element:
                    print subelement,'element'
        else:
            item = RItem() # create Index Item
            item['html_content'] = each
            print each
            yield item

部分结果格式正确，但某些没有小节的部分会被分解为单个元素。

我希望每个部分都是单独的。我的意思是因为1节有其他部分。我想循环遍历这些部分并单独获取它们，以便我可以跟踪循环。由于某些部分没有子部分，因此无需循环使用。

在BeautifulSoup中有更好的方法吗？我想要以下输出

＆＃13;

    <section>
        <h2>Title1</h2>
        <p>Text1</p>
        <p>Text1</p>
     </section>
  <section>
        <h2>Title2</h2>
        <p>Text2</p>
        <p>Text2</p>
     </section>
  <section>
        <h2>Title3</h2>
        <p>Text3</p>
        <p>Text3</p>
     </section>
 
    <section>
            <h2>Title2-1</h2>
            <p>Text2-1</p>
            <p>Text2-1</p>
    </section>
    <section>
            <h2>Title3-1</h2>
            <p>Text3-1</p>
            <p>Text3-1</p>
    </section>

＆＃13;

Answer 1

检查这种方法。它是您提供的数据的通用。

data = """
<section>
    <section>
        <h2>Title1</h2>
        <p>Text1</p>
        <p>Text1</p>
     </section>
  <section>
        <h2>Title2</h2>
        <p>Text2</p>
        <p>Text2</p>
     </section>
  <section>
        <h2>Title3</h2>
        <p>Text3</p>
        <p>Text3</p>
     </section>
  </section>
<section>
        <h2>Title2-1</h2>
        <p>Text2-1</p>
        <p>Text2-1</p>
</section>
<section>
        <h2>Title3-1</h2>
        <p>Text3-1</p>
        <p>Text3-1</p>
</section>
"""
from bs4 import BeautifulSoup

soup = BeautifulSoup(data)

sections = soup.find_all('section')


for each in sections: #iterate over loop [above sections]
    if each.find('section'):
        continue
    else:
        print each.prettify()

美丽的汤迭代html标记

1 个答案: