我确定之前应该由Photoshop脚本编写者讨论过。我写了一个解决方案如下。我认为它在逻辑上是对的,但结果并不正确。任何人都可以帮助检查代码中的错误,或者对此主题有什么想法?我想获取文档中的所有图层。
代码:
function getAllLayersInLayerSets(layerNodes) {
var retList = [];
for (var i=0; i<layerNodes.length; i++) {
if(layerNodes[i].layerSets.length > 0)
{
var tmp = getAllLayersInLayerSets(layerNodes[i].layerSets);
var j = (tmp == null) ? -1 : tmp.length-1;
while(tmp && j>=0)
{
retList.push(tmp[i]);
j--;
}
}
for(var layerIndex=0; layerIndex < layerNodes[i].artLayers.length; layerIndex++)
{
var layer=layerNodes[i].artLayers[layerIndex];
retList.push(layer);
}
}
return retList;
}
非常感谢任何帮助或讨论。
答案 0 :(得分:4)
我知道这是一个旧线程,但这可能对某人有用。
我正在寻找能够让我在Photoshop中获得所有ArtLayers的功能,包括嵌套在群组中的图层。上面的函数返回undefined,所以我修改了它并让它工作。
var doc = app.activeDocument;
var allLayers = [];
var allLayers = collectAllLayers(doc, allLayers);
function collectAllLayers (doc, allLayers){
for (var m = 0; m < doc.layers.length; m++){
var theLayer = doc.layers[m];
if (theLayer.typename === "ArtLayer"){
allLayers.push(theLayer);
}else{
collectAllLayers(theLayer, allLayers);
}
}
return allLayers;
}
答案 1 :(得分:0)
要获得所有图层(和子图层),您必须具有递归函数
var allLayers = new Array();
var theLayers = collectAllLayers(app.activeDocument, 0);
function collectAllLayers (theParent, level)
{
for (var m = theParent.layers.length - 1; m >= 0; m--)
{
var theLayer = theParent.layers[m];
if (theLayer.typename != "ArtLayer")
{
allLayers.push(level + theLayer.name);
collectAllLayers(theLayer, level + 1)
}
}
}
答案 2 :(得分:0)
Ghoul Fool的帖子略有扩展,只能获得活动文档中的所有可见艺术图层。 :P
// Get layers in a document
var sourceDocument = app.activeDocument;
var visibleLayers = [];
var visibleLayers = collectAllLayers(sourceDocument, visibleLayers);
// Print out total layers found
alert(visibleLayers.length);
// Recursively get all visible art layers in a given document
function collectAllLayers (parent, allLayers)
{
for (var m = 0; m < parent.layers.length; m++)
{
var currentLayer = parent.layers[m];
if (currentLayer.typename === "ArtLayer")
{
if(currentLayer.visible)
{
allLayers.push(currentLayer);
}
}
else
{
collectAllLayers(currentLayer, allLayers);
}
}
return allLayers;
}
答案 3 :(得分:0)
function selectAllLayers() {
var desc29 = new ActionDescriptor();
var ref23 = new ActionReference();
ref23.putEnumerated(charIDToTypeID('Lyr '), charIDToTypeID('Ordn'), charIDToTypeID('Trgt'));
desc29.putReference(charIDToTypeID('null'), ref23);
executeAction(stringIDToTypeID('selectAllLayers'), desc29, DialogModes.NO);
}