Question

我知道这有用（返回true）

var arr1 = [1, 'a', 2, 'b', 3];
var arr2 = [1, 2, 3];

var isSuperset = arr2.every(function (val) { return arr1.indexOf(val) >= 0; });

但是说array1由对象组成，我想根据对象的某个属性检查array2：

var object1 = {name:'one'}
var object2 = {name:'two'}
var object3 = {name:'three'}

var arr1 = [object1,object2,object3];
var arr2 = ['one','two'];
var isSuperset = arr2.every(function (val) { return arr1.indexOf(val) >= 0; });

如何确保每个函数都对name属性进行检查？

Answer 1

var object1 = {name: 'one'};
var object2 = {name: 'two'};
var object3 = {name: 'three'};

var arr1 = [object1,object2,object3];
var arr2 = ['one','two'];

// solution
var names = arr1.map(function(obj) { 
  return obj.name; 
});

var isSuperset = arr2.every(function(val) { 
  return names.indexOf(val) >= 0;
});

alert(isSuperset);

检查数组是否是另一个数组的子集（但是检查属性）

1 个答案: