查看:
<div>
<input type='file' name="active_board_data[pictures][]">
<input type='text' name="active_board_data[name][]">
<input type='text' name="active_board_data[description][]">
</div>
<div>
<input type='file' name="active_board_data[pictures][]">
<input type='text' name="active_board_data[name][]">
<input type='text' name="active_board_data[description][]">
</div>
<div>
<input type='file' name="active_board_data[pictures][]">
<input type='text' name="active_board_data[name][]">
<input type='text' name="active_board_data[description][]">
</div>
提交后var_dump($_POST['active_board_data']);
显示
array (size=3)
'name_description_input' =>
array (size=3)
0 => string '' (length=0)
1 => string '<p>sdfv</p>' (length=11)
2 => string '' (length=0)
'relevant_details_description_input' =>
array (size=3)
0 => string '<p>dsrvsd</p>' (length=13)
1 => string '' (length=0)
2 => string '<p>sdfvr</p>' (length=12)
'pictures' =>
array (size=1)
0 => string '' (length=0)
var_dump($_FILES['active_board_data']);
显示
array (size=5)
'name' =>
array (size=1)
'pictures' =>
array (size=3)
0 => string 'active_trustees_26-Oct-2014__08_10_00__25408.jpg' (length=48)
1 => string 'active_trustees_26-Oct-2014__08_10_18__7037.jpg' (length=47)
2 => string 'active_trustees_26-Oct-2014__08_10_18__3779.jpg' (length=47)
'type' =>
array (size=1)
'pictures' =>
array (size=3)
0 => string 'image/jpeg' (length=10)
1 => string 'image/jpeg' (length=10)
2 => string 'image/jpeg' (length=10)
'tmp_name' =>
array (size=1)
'pictures' =>
array (size=3)
0 => string 'C:\wamp\tmp\php128F.tmp' (length=23)
1 => string 'C:\wamp\tmp\php12A0.tmp' (length=23)
2 => string 'C:\wamp\tmp\php12B0.tmp' (length=23)
'error' =>
array (size=1)
'pictures' =>
array (size=3)
0 => int 0
1 => int 0
2 => int 0
'size' =>
array (size=1)
'pictures' =>
array (size=3)
0 => int 49543
1 => int 52657
2 => int 29884
这是在表单提交后在php中的同一个数组上同时拥有文件和文本的正确方法吗?或者我应该更改标记? 注意:我正在动态创建 div 。请帮助。谢谢。 这是提交表格的图片:
答案 0 :(得分:2)
您仍然可以同时访问这两者,但不使用foreach
结构,而是使用for
结构,如下所示:
$szFiles = sizeof ($_FILES['active_board_data']['name']['pictures']);
for ($i=0; $i<$szFiles; $i++)
{
$file_name = $_FILES['active_board_data']['name']['pictures'][$i];
$name = $_POST['active_board_data']['name'][$i];
$description = $_POST['active_board_data']['description'][$i];
}
暂且不说:对我而言,框架的最佳部分是使用它的一些辅助功能,例如CI文件上传器帮助程序系统:https://ellislab.com/codeigniter/user-guide/libraries/file_uploading.html。