Question

所以我有这样的东西，但它只是在它的末尾输出1的链接。

var pagelink = "http://www.roblox.com/catalog/browse.aspx?CatalogContext=1&Subcategory=2&Keyword=&CurrencyType=0&pxMin=0&pxMax=0&SortType=4&SortAggregation=3&SortCurrency=0&PageNumber=";
 var num = 1;
   var maxnum = 32;
   for(var i = num; i <= maxnum; i++){
  pagelink + num
}

所以输出才会返回：

http://www.roblox.com/catalog/browse.aspx?CatalogContext=1&Subcategory=2&Keyword=&CurrencyType=0&pxMin=0&pxMax=0&SortType=4&SortAggregation=3&SortCurrency=0&PageNumber=1

Answer 1

首先 - 你需要做一些js训练。查看eloquentjavascript.net并前往城镇。

答案：

var pagelink = "http://www.roblox.com/catalog/browse.aspx?CatalogContext=1&Subcategory=2&Keyword=&CurrencyType=0&pxMin=0&pxMax=0&SortType=4&SortAggregation=3&SortCurrency=0&PageNumber=";
var num = 1;
var maxnum = 32;
// You need something to put the output in. Here's an array.
var links = [];
for(var i = num; i <= maxnum; i++) {
  links.push(pagelink + i);
}
return links;

Answer 2

 var pagelink = "http://www.roblox.com/catalog/browse.aspx?CatalogContext=1&Subcategory=2&Keyword=&CurrencyType=0&pxMin=0&pxMax=0&SortType=4&SortAggregation=3&SortCurrency=0&PageNumber=";
 var results = [];
 for(var i = 0; i <= **however many links you want**; i++){
   results.push(pagelink + (i % 32 + 1));
 }
 results // or if you want it delimited, results.join('\n') or whatever other delimiter you want

您的结果将存储在结果中，您可以将其返回（如果在函数中）或将其用于您需要的结果

使链接计数从1到32并重置为1？

2 个答案: