Question

我正在尝试在输入时收到通知。

<script type="text/javascript" src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script type="text/javascript" src="/js/strophe.min.js"></script>

connection.addHandler(onNotificationReceived, null, "message", "chat", null,  null);

function onNotificationReceived(msg)
{

    var composing = $(msg).find('composing'),
        paused = $(msg).find('paused'),
        active = $(msg).find('active'),
        jid = $(msg).attr('from');

        if (composing.length > 0)
        {
            $('.chat-feedback').css('display', 'block');
            alert(1);
        }

        if (paused.length > 0)
        {
            $('.chat-feedback').css('display', 'none');
            alert(2);
        }

        if (active.length > 0)
        {
            $('.chat-feedback').css('display', 'none');
            alert(3);
        }

    return true;
}

但它不起作用：（

请帮忙！

PS。 Сomplete脚本http://sitechat.ru/tests/chat1/

Answer 1

您需要在onNotificationReceived(msg)

中将响应解析为XML

var msg = $.parseXML(msg);

而且我认为你的意思是

jid = $(msg).find('message').attr('from');

收到Strophe.js通知（撰写）

1 个答案: