我有多个“数据表”文本文件,这些文件与工作中的程序一起使用,需要从中获取值并将它们全部组合到电子表格中。
文本文件的格式如下:
[File]
DescText = "1756-IF16H 16 Channel Hart Analog Input Module";
CreateDate = 04-07-10;
CreateTime = 10:29;
Revision = 1.1;
HomeURL = "http://www.ab.com/networks/eds/XX/0001000A00A30100.eds";
[Device]
VendCode = 1;
VendName = "Allen-Bradley";
ProdType = 10;
ProdTypeStr = "Multi-Channel Analog I/O with HART";
ProdCode = 163;
MajRev = 1;
MinRev = 1;
ProdName = "1756-IF16H/A";
Catalog = "1756-IF16H/A";
Icon = "io_brown.ico";
标签在所有文件中都是一致的,每行以分号结束[; ]所以我假设这应该很容易。我需要将“DescText”,“VendCode”,“ProdType”,“MajRev”,“MinRev”和“ProdName”拖到单独的列中。
大约有100个单独的数据文件,每个文件都有一个荒谬的文件名,所以我希望让宏只通过并打开文件夹中的每一个。
答案 0 :(得分:1)
感谢您的帮助,以下是我为此特定问题提出的解决方案
Sub OpenFiles()
Dim MyFolder As String
Dim MyFile As String
MyFolder = "[directory of files]"
MyFile = Dir(MyFolder & "\*.txt")
Dim filename As String
Dim currentrow As Integer: currentrow = 2
Do While Myfile <> "" 'This will go through all files in the directory, "Dir() returns an empty string at the end of the list
'For i = 1 To 500 'this was my debug loop to only go through the first 500 files at first
filename = MyFolder & "\" & MyFile 'concatinates directory and filename
Open filename For Input As #1
Do Until EOF(1) 'reads the file Line by line
Line Input #1, textline
'Text = Text & textline
If textline = "" Then 'error handler, if line was empty, ignore
Else
Dim splitline() As String
splitline() = Split(textline, "=", -1, vbTextCompare)
'because of how my specific text was formatted, this splits the line into 2 strings. The Tag is in the first element, the data in the second
If IsError(splitline(0)) Then
splitline(0) = ""
End If
Select Case Trim(splitline(0)) 'removes whitespace
Case "DescText"
currentrow = currentrow + 1
'files that didn't have a description row, resulted in empty rows in the spreadsheet.
ActiveSheet.Range("A" & currentrow).Cells(1, 1).Value = splitline(1)
Case "Revision"
ActiveSheet.Range("B" & currentrow).Cells(1, 1).Value = splitline(1)
Case "ProdCode"
ActiveSheet.Range("C" & currentrow).Cells(1, 1).Value = splitline(1)
Case "ProdType"
ActiveSheet.Range("D" & currentrow).Cells(1, 1).Value = splitline(1)
'...etc. etc... so on for each "tag"
End Select
End If
Loop
Close #1
MyFile = Dir() 'reads filename of next file in directory
'currentrow = currentrow + 1
'Next i
Loop
End Sub
答案 1 :(得分:0)
这里我将如何解决完整的任务:
Private Sub importFiles(ByVal pFolder As String)
' create FSO
Dim oFSO As Object
Set oFSO = CreateObject("Scripting.FileSystemObject")
' create folder
Dim oFolder As Object
Set oFolder = oFSO.getFolder(pFolder)
' go thru the folder
Dim oFile As Object
For Each oFile In oFolder.Files
' check if is a text file
If UCase(Right(oFile.Name, 4)) = ".TXT" Then
Debug.Print "process file: " & oFolder.Path & "\" & oFile.Name
readFile oFolder.Path & "\" & oFile.Name
End If
Next
' clean up
Set oFolder = Nothing
Set oFSO = Nothing
End Sub
Private Sub readFile(ByVal pFile As String)
' get new file handle
Dim hnd As Integer
hnd = FreeFile
' open file
Open pFile For Input As hnd
Dim sContent As String
Dim sLine As String
' read file
Do Until EOF(hnd)
Line Input #hnd, sLine
sContent = sContent & sLine
Loop
' close file
Close hnd
' extract requiered data
Debug.Print getValue(sContent, "ProdName")
Debug.Print getValue(sContent, "DescText")
End Sub
Private Function getValue(ByVal pContent As String, ByVal pValueName As String) As String
Dim sRet As String
sRet = ""
If InStr(pContent, pValueName) Then
pContent = Mid(pContent, InStr(pContent, pValueName) + Len(pValueName) + 2)
sRet = Left(pContent, InStr(pContent, ";") - 1)
sRet = Trim(sRet)
End If
getValue = sRet
End Function
整体而言,该解决方案包含3个不同的程序:
importFiles读取给定目录的内容(必须作为参数移交),如果找到.txt文件,则调用readFile()并将文件的完整路径传递给它
readFile()打开文本文件并将内容存储在字符串变量中。完成此操作后,它会为您所关注的每个值调用getValue。
getValue分析给定内容并提取给定值。
只需调整getValue()的调用,即可获得所有被调用的值并存储它们而不是通过debug.print显示,并使用正确的目录调用第一个过程,如 importFiles“C:\ Temp “强>