Question

以下xml是由需要由Java应用程序转换为Employee类型的对象的系统生成的。

<?xml version="1.0" encoding="utf-8"?>
<Employee xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
 <Designation>Executive</Designation>
 <Name>Praveen Kumar</Name>
 <Salary>90000</Salary>
<BankAccount>10111</BankAccount>
</Employee>

如何使用XmlDecoder的readObject方法反序列化上述XML而不转换由另一个系统生成的xml文件？

Answer 1

以下是处理用例的方法：

Java模型

以下课程将用于此答案：

package forum26609152;

public class Employee {

    private String designation;
    private String name;
    private int salary;
    private String bankAccount;

    public String getDesignation() {
        return designation;
    }

    public void setDesignation(String designation) {
        this.designation = designation;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getSalary() {
        return salary;
    }

    public void setSalary(int salary) {
        this.salary = salary;
    }

    public String getBankAccount() {
        return bankAccount;
    }

    public void setBankAccount(String bankAccount) {
        this.bankAccount = bankAccount;
    }

}

XMLEncoder /的XMLDecoder

以下是XMLEncoder / XMLDecoder期望使用的XML。它与您问题中的XML非常不同。 XMLEncoder / XMLDecoder不适合您的用例。

<?xml version="1.0" encoding="UTF-8"?>
<java version="1.7.0_60" class="java.beans.XMLDecoder">
 <object class="forum26609152.Employee">
  <void property="bankAccount">
   <string>10111</string>
  </void>
  <void property="designation">
   <string>Executive</string>
  </void>
  <void property="name">
   <string>Praveen Kumar</string>
  </void>
  <void property="salary">
   <int>90000</int>
  </void>
 </object>
</java>

JAXB

JAXB是用于对象到XML绑定的标准API。自Java SE 6以来，JDK / JRE中已包含一个实现，因此您已经拥有它。

<强>员工

Java和XML之间的映射是通过注释配置的。下面是将Java对象映射到您的问题中的XML所需的注释。

import javax.xml.bind.annotation.*;

@XmlRootElement(name="Employee")
@XmlType(propOrder = {"designation", "name", "salary", "bankAccount"})
public class Employee {

    private String designation;
    private String name;
    private int salary;
    private String bankAccount;

    @XmlElement(name="Designation")
    public String getDesignation() {
        return designation;
    }

    public void setDesignation(String designation) {
        this.designation = designation;
    }

    @XmlElement(name="Name")
    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    @XmlElement(name="Salary")
    public int getSalary() {
        return salary;
    }

    public void setSalary(int salary) {
        this.salary = salary;
    }

    @XmlElement(name="BankAccount")
    public String getBankAccount() {
        return bankAccount;
    }

    public void setBankAccount(String bankAccount) {
        this.bankAccount = bankAccount;
    }

}

演示代码

下面是您需要编写的代码，以便将XML读入对象形式，然后将其输出回XML。

import javax.xml.bind.*;
import java.io.File;

public class JaxbDemo {

    public static void main(String[] args) throws Exception {
        JAXBContext jc = JAXBContext.newInstance(Employee.class);

        Unmarshaller unmarshaller = jc.createUnmarshaller();
        File xml = new File("input.xml");
        Employee employee = (Employee) unmarshaller.unmarshal(xml);

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(employee, System.out);
    }

}

<强> input.xml中/输出

正如您所看到的，这是您问题中的XML：

<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Employee>
    <Designation>Executive</Designation>
    <Name>Praveen Kumar</Name>
    <Salary>90000</Salary>
    <BankAccount>10111</BankAccount>
</Employee>

在不转换xml文件的情况下反序列化XML文件

1 个答案:

Java模型

XMLEncoder /的XMLDecoder

JAXB