Question

我有表tableA如下：

+--------+----------------------+
|   Id   |          Ref         |
+--------+----------------------+
|    1   |    RN1-102,RN2-103   |  
|    2   |    RN1-106           |
|    3   |    RN2-203           |
|    4   |    NULL              |
|    5   |    RN1-104|,RN2-107  |
|    6   |    RN1-101,RN2-105   |
|    7   |    RN1-100,RN2-109   |
+--------+----------------------+

我需要一个输出（来自tableA的不同参考），如下所示：

+--------------------+
| Distinct Ref data  |
+--------------------+
|      RN1-100       |
|      RN1-101       |
|      RN1-102       |
|      RN1-104       |
|      RN1-106       |
|      RN2-103       |
|      RN2-105       |
|      RN7-107       |
|      RN2-109       |
|      RN2-203       |
+--------------------+

我尝试使用以下查询：

select distinct Ref from tableA

请帮帮我..

Answer 1

尝试使用此

SELECT distinct Split.a.value('.', 'VARCHAR(100)') REF
           FROM   (select ID,Cast ('<M>'
                                + replace(Replace(REF, ',', '</M><M>'),'&','&amp;')
                                + '</M>' AS XML) AS Data from #Table) AS A
                  CROSS APPLY Data.nodes ('/M') AS Split(a)

Answer 2

此问题类似于我之前回答的this question。我在答案中提出了两种方法，一种是使用递归而不是。

但如果您已经有一个表存储了ref个键，那么您有第三个选择：

create table ref_table (ref varchar(10), ref_name varchar(100), primary key (ref));

select
    r.ref
from 
    ref_table r
where 
    EXISTS (
        select 1 
        from tableA a
        where a.ref like '%'+r.ref+'%'  -- or ','+a.ref+',' like '%,'+r.ref+',%' 
        )

SQL FIDDLE DEMO

Answer 3

SELECT distinct Split.a.value('.', 'VARCHAR(100)') REF
           FROM   (select ID,Cast ('<M>'
                                + replace(Replace(REF, ',', '</M><M>'),'&','&amp;')
                                + '</M>' AS XML) AS Data from #Table) AS A
                  CROSS APPLY Data.nodes ('/M') AS Split(a)

如何使用SQL查询从字符串列表中获取字符串

3 个答案: