Question

如何在多维数组中获取数组的值...在另一个数组中？

我希望在以下代码中按升序获取test的值。

我尝试使用for和foreach循环，但在引用多维数组的元素时遇到了问题。

static void Main(string[] args)
{
    string[][,][] test = { new string[,][]{{
                                               new string[]{"test1","test2","test3"},
                                               new string[]{"test4","test6","test6"}
                                           },
                                           {
                                               new string[]{"test7","test7","test9"},
                                               new string[]{"test10","test11","test12"}
                                           }},
                           new string[,][]{{
                                               new string[]{"test13","test14","test15"},
                                               new string[]{"test16","test17","test18"}
                                           },
                                           {
                                               new string[]{"test19","test20","test21"},
                                               new string[]{"test22","test23","test24"}
                                           }}
                         };
    for (int a = 0; a < test.Count(); a++ )
    {
        foreach(var am in test[a])
        {
            for (int ama = 0; ama < am.Count(); ama++)
            {
                Console.WriteLine("{0}",test[a][0,0][ama].ToString()); //what should I put in [0,0]?
            }
        }
    }
    Console.ReadKey();
}

Answer 1

为什么不：

Console.WriteLine("{0}", am[ama].ToString());

Answer 2

您可以使用foreach，而不是使用for，如下所示：

  for ( int a = 0; a < test.Count(); a++ )
  {
    string[,][] ta = test[a];
    for( int i1 = 0; i1 < ta.GetLength( 0 ); i1++ )
    {
      for( int i2 = 0; i2 < ta.GetLength( 1 ); i2++ )
      {
        string[] am = ta[i1, i2];
        for ( int ama = 0; ama < am.Count(); ama++ )
        {
          Console.WriteLine( "{0}", test[ a ][ i1, i2 ][ ama ].ToString() );
        }
      }
    }

Answer 3

莱昂内尔，

以下是您的代码：

static void Main(string[] args)
    {
        string[][,][] test = { new string[,][]{{
                                                   new string[]{"test1","test2","test3"},
                                                   new string[]{"test4","test5","test6"}
                                               },
                                               {
                                                   new string[]{"test7","test8","test9"},
                                                   new string[]{"test10","test11","test12"}
                                               }},
                               new string[,][]{{
                                                   new string[]{"test13","test14","test15"},
                                                   new string[]{"test16","test17","test18"}
                                               },
                                               {
                                                   new string[]{"test19","test20","test21"},
                                                   new string[]{"test22","test23","test24"}
                                               }}
                             };
        for (int a = 0; a < test.Count(); a++)
        {
            foreach(string[] am in test[a])
            {
                for (int ama = 0; ama < am.Count(); ama++)
                {
                    Console.WriteLine("{0}", am[ama].ToString()); //Reference to the inside loop
                }
            }
        }
        Console.ReadKey();
    }

无需在print语句中引用整个数组。您只需要引用内部循环。希望有所帮助。

祝福，比尔

在数组中的多维数组中获取数组的值

3 个答案: