我是Android开发的小伙子,我正试图想出一种使用语音识别启动我的应用程序的方法。我想在用户首次登录后开始在后台运行的RecognitionService。我希望服务能够持续运行并允许用户使用关键字启动应用程序。我将允许用户在设置活动中停止服务。目前,我能够启动服务并使其在后台运行,但我无法想象如何在RecognitionService中调用onStartListening方法。任何帮助解决这个问题都非常感谢。
我的代码
public class VoiceRecognitionService extends RecognitionService {
private SpeechRecognizer m_EngineSR;
@Override
public void onCreate() {
super.onCreate();
Log.e("SimpleVoiceService", "Service started");
}
@Override
public void onDestroy() {
super.onDestroy();
Log.e("SimpleVoiceService", "Service stopped");
}
@Override
protected void onCancel(Callback listener) {
m_EngineSR.cancel();
}
@Override
protected void onStartListening(Intent recognizerIntent, Callback listener) { //<--How Do I call this method?
m_EngineSR.setRecognitionListener(new VoiceResultsListener(listener));
m_EngineSR.startListening(recognizerIntent);
}
@Override
protected void onStopListening(Callback listener) {
m_EngineSR.stopListening();
}
/**
*
*/
private class VoiceResultsListener implements RecognitionListener {
private Callback m_UserSpecifiedListener;
/**
*
* @param userSpecifiedListener
*/
public VoiceResultsListener(Callback userSpecifiedListener) {
m_UserSpecifiedListener = userSpecifiedListener;
}
@Override
public void onBeginningOfSpeech() {
try {
m_UserSpecifiedListener.beginningOfSpeech();
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onBufferReceived(byte[] buffer) {
try {
m_UserSpecifiedListener.bufferReceived(buffer);
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onEndOfSpeech() {
try {
m_UserSpecifiedListener.endOfSpeech();
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onError(int error) {
try {
m_UserSpecifiedListener.error(error);
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onEvent(int eventType, Bundle params) { ; }
@Override
public void onPartialResults(Bundle partialResults) {
try {
m_UserSpecifiedListener.partialResults(partialResults);
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onReadyForSpeech(Bundle params) {
try {
m_UserSpecifiedListener.readyForSpeech(params);
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onResults(Bundle results) {
try {
m_UserSpecifiedListener.results(results);
Log.e("SimpleVoiceService Results:", "Service stopped");
ArrayList<String> result = results.getStringArrayList("results_recognition");
Log.e("SimpleVoiceService Results:", result.get(0));
if (result.isEmpty() == false) {
for (int i = 0; i<(result.size()-1);i++) {
if(result.get(i).equals("shoot back")||result.get(i).equals("Launch App")){
Intent intent2 = new Intent("com.bmoney.testapp.MAIN_ACTIVITY");
startActivity(intent2);
break;
}
}
}
} catch (RemoteException e) {
e.printStackTrace();
}
}
@Override
public void onRmsChanged(float rmsdB) {
try {
m_UserSpecifiedListener.rmsChanged(rmsdB);
} catch (RemoteException e) {
e.printStackTrace();
}
}
}
}
清单
<service android:name="com.bmoney.testapp.VoiceRecognitionService" android:exported="true" android:enabled="true">
<intent-filter>
<action android:name="android.speech.RecognitionService" />
<category android:name="android.intent.category.DEFAULT" />
</intent-filter>
</service>
答案 0 :(得分:0)
虽然我没有机会对此进行测试,但我认为答案在于this android开发者博客文章。
这个实现虽然使用了“Ok Google”(我不知道这是否会让你烦恼)。
简而言之,您必须实施seachable activity并在AndroidManifest中添加此内容:
<activity android:name=".SearchableActivity">
<intent-filter>
<action android:name="com.google.android.gms.actions.SEARCH_ACTION"/>
<category android:name="android.intent.category.DEFAULT"/>
</intent-filter>
</activity>