我正在制作购物车系统,我的会话正在使用foreach()函数显示。在这个函数中,我有一个名为$ item_price的变量。我希望所有$ item_price都加起来,以便我最终获得总计。
怎么可以这样做?我不知道应该如何解决这个问题:/
这是我的foreach()代码:
foreach($session_cart as $cart_items) {
$fetch_info = mysql_query("SELECT * FROM `shop_items` WHERE item_id = '$cart_items'");
while($shop_items = mysql_fetch_array($fetch_info)) {
$item_id = $shop_items['item_id'];
$item_name = $shop_items['item_name'];
$item_quantity = count(array_keys($session_quantity, $item_id));
$item_price = $shop_items['item_price'] * $item_quantity; }
$cartOutput .= '<h2>'.$item_name.'</h2>';
$cartOutput .= '<a> Quantity: '.$item_quantity.'</a><br>';
$cartOutput .= '<a> Price: '.number_format((float)$item_price, 2, '.', '').' USD</a><br>';
$cartOutput .= '<a> ID: '.$item_id.'</a><br><br>';
}
答案 0 :(得分:0)
$total = 0;
foreach($array as $row)
{
$total += $row['item_price'];
//the rest of your code in foreach
}
echo $total;
答案 1 :(得分:0)
使用更新的代码:
$total = 0;
foreach($session_cart as $cart_items) {
$fetch_info = mysql_query("SELECT * FROM `shop_items` WHERE item_id = '$cart_items'");
// while($shop_items = mysql_fetch_array($fetch_info)) { //<- No need of loop here as only one will be returned everytime
$shop_items = mysql_fetch_assoc($fetch_info); //<- use this instead
$item_id = $shop_items['item_id'];
$item_name = $shop_items['item_name'];
$item_quantity = count(array_keys($session_quantity, $item_id));
$item_price = $shop_items['item_price'] * $item_quantity;
//} //<- Closing while loop removed
$cartOutput .= '<h2>'.$item_name.'</h2>';
$cartOutput .= '<a> Quantity: '.$item_quantity.'</a><br>';
$cartOutput .= '<a> Price: '.number_format((float)$item_price, 2, '.', '').' USD</a><br>';
$cartOutput .= '<a> ID: '.$item_id.'</a><br><br>';
$total+=$item_price; //<- Sums up for grand total
}
echo $total; //<- shows grand total