Question

我完成了一项练习计划。它打印得很好，但问题是输出的最后三行是不准确的。每次我运行程序时，它会生成不同的输出，在键之间交替。我无法找到让它正确出现的方法（如程序中所述）

def main( ):
    zip_dictionary = {}
    zip_dictionary = update_dictionary(zip_dictionary, "CAM", "1427")
    zip_dictionary = update_dictionary(zip_dictionary, "UofM", "1427")
    zip_dictionary = update_dictionary(zip_dictionary, "ZIT", "1423-503")
    zip_dictionary = update_dictionary(zip_dictionary, "MCOC", "1423")
    zip_dictionary = update_dictionary(zip_dictionary, "NAZARETH", "1418")
    zip_dictionary = update_dictionary(zip_dictionary, "OCC", "1420")

    for key in zip_dictionary:
        print(key, zip_dictionary[key])

    for i in range(2):
        print(zip_dictionary.popitem( ))

    for value in zip_dictionary:
        print(zip_dictionary[value], key)

def update_dictionary(dct, key, value):
    dct[key] = value
    return dct
main( )

Answer 1

使用OrderedDict，不要打扰update_dictionary，并且在重复key时不要打印value。

from collections import OrderedDict

def main( ):
    zip_dictionary = OrderedDict()
    zip_dictionary["CAM"] = "1427"
    zip_dictionary["UofM"] = "1427"
    zip_dictionary["ZIT"] = "1423-503"
    zip_dictionary["MCOC"] = "1423"
    zip_dictionary["NAZARETH"] = "1418"
    zip_dictionary["OCC"] = "1420"

    print "\nContents of dict:"
    for key in zip_dictionary:
        print(key, zip_dictionary[key])

    print "\nPopping items:"
    for i in range(2):
        print(zip_dictionary.popitem( ))

    print "\nRemaining items:"
    for key in zip_dictionary:
        print(key, zip_dictionary[key])

main( )

结果：

Contents of dict:
('CAM', '1427')
('UofM', '1427')
('ZIT', '1423-503')
('MCOC', '1423')
('NAZARETH', '1418')
('OCC', '1420')

Popping items:
('OCC', '1420')
('NAZARETH', '1418')

Remaining items:
('CAM', '1427')
('UofM', '1427')
('ZIT', '1423-503')
('MCOC', '1423')

Answer 2

如果你想得到相同的＆＃39;每次您可以根据字母顺序对键进行排序。

for sorted_key in [key in zip_dictionary].sort():
    print(sorted_key , zip_dictionary[sorted_key])

如果他们需要按此顺序，您还可以维护带有键的有序列表。您也不需要在update_dictionary函数中返回字典，因为它是一个可变对象。

def update_dictionary(dct, lst, key, value):
    dct[key] = value
    if not key in lst:
        lst.append(key)

def main( ):
    zip_dictionary = {}
    zip_list = []
    update_dictionary(zip_dictionary, zip_list, "CAM", "1427")
    update_dictionary(zip_dictionary, zip_list, "UofM", "1427")
    update_dictionary(zip_dictionary, zip_list, "ZIT", "1423-503")
    update_dictionary(zip_dictionary, zip_list, "MCOC", "1423")
    update_dictionary(zip_dictionary, zip_list, "NAZARETH", "1418")
    update_dictionary(zip_dictionary, zip_list, "OCC", "1420")

    for key in zip_list:
        print(key, zip_dictionary[key])

Python字典程序输出问题

2 个答案: