Question

我有问题将下面的查询分组为每月汇总。表与一个表交叉连接以获取速率，内部与另一个连接，其中只包含日期以显示表中数据不存在的日期的空值（客户端请求）它适用于下面的每日分组。请如何每月分组。

Select * from(select [Letter_Date] [Date],Council
SUM([Total_Corr])*[Rate][Total]
FROM Correspondence
cross join 
Input_Variable_Price
where [Revenue_Name] = 'Correspondence'
group by [Letter_Date],Council)AS ED

RIGHT JOIN 
(Select '21'[No],b_date,[Revenue_Name][Report],[Unit],[Rate]
From Blank_dates 
cross join 
Input_Variable_Price
where [Revenue_Name] = 'Correspondence') AS BD
ON ED.Date = BD.[b_date]

干杯

Answer 1

我会使用以下内容：添加SELECT所需的任何其他聚合，以及GROUP BY中您需要的任何项目。

Select DATEADD(month, DATEDIFF(month, 0, [Date]), 0) AS StartOfMonth, SUM(Total)
from
  (
    select [Letter_Date] [Date],Council,
        SUM([Total_Corr])*[Rate] [Total]
    FROM 
        Correspondence
         cross join 
        Input_Variable_Price
    where [Revenue_Name] = 'Correspondence'
    group by [Letter_Date],Council
  )AS ED

RIGHT JOIN 
  (
    Select 
        '21'[No],
        b_date,
        [Revenue_Name][Report],
        [Unit],
        [Rate]
    From 
        Blank_dates 
         cross join 
        Input_Variable_Price
    where [Revenue_Name] = 'Correspondence'
  ) AS BD ON 
    ED.Date = BD.[b_date]
GROUP BY DATEADD(month, DATEDIFF(month, 0, [Date]), 0)

每月分组加入

1 个答案: