fig = plt.figure(num=1)
ax=fig.add_subplot(111)
def f1(x):
return 1/x
def f2(x):
return 2/x
def f3(x):
return np.sqrt(x**2-1)
def f4(x):
return np.sqrt(x**2-2)
s= np.arange(np.sqrt(2),5,0.05)
t=np.arange(1,5,0.05)
y1=f1(t)
y2=f2(t)
y3=f3(t)
y4=f4(s)
ax.plot(t,y1,'k-',t,y2,'k-',t,y3,'k-',s,y4,'k-')
plt.xlim([1.1,2.1])
plt.ylim([0.5,1.5])
plt.show()
我想填充这四个函数描述的曲线之间的区域。在这种情况下,不确定如何使用fill_between
选项。
答案 0 :(得分:2)
您只能fill_between
两条曲线而不是四条曲线。因此,使用您拥有的四条曲线,您可以创建两个我在下面显示的曲线y5
和y6
,然后将它们用于fill_between
它们。示例如下所示:
我还使用符号绘制了各个函数,以便很容易看到刚创建的不同新曲线......
import pylab as plt
import numpy as np
fig = plt.figure(num=1)
ax=fig.add_subplot(111)
def f1(x): return 1/x
def f2(x): return 2/x
def f3(x): return np.sqrt(x**2-1)
def f4(x): return np.sqrt(x**2-2)
t=np.arange(1,5,1e-4) # use this if you want a better fill
t=np.arange(1,5,0.05)
y1=f1(t)
y2=f2(t)
y3=f3(t)
y4=f4(t*(t**2>2) + np.sqrt(2)*(t**2<=2) ) # Condition checking
y5 = np.array(map(min, zip(y2, y3)))
y6 = np.array(map(max, zip(y1, y4)))
ax.plot(t,y1, 'red')
ax.plot(t,y2, 'blue')
ax.plot(t,y3, 'green')
ax.plot(t,y4, 'purple')
ax.plot(t, y5, '+', ms=5, mfc='None', mec='black')
ax.plot(t, y6, 's', ms=5, mfc='None', mec='black')
ax.fill_between(t, y5, y6, where=y5>=y6)
plt.xlim([1.1,2.1])
plt.ylim([0.5,1.5])
plt.show()