每当我运行它时，似乎循环继续播放工作，但是只要conputerChoose执行randomGenerator，游戏结果就不会正确输出。请帮忙。我是java的新手，我们只想使用3种方法 - 说明，playGame和computerChoose。我们还假设使用用户控制的循环来继续工作。我似乎无法做到这一点，我仍然需要添加一个循环来计算游戏的播放时间，赢得的次数和计算机赢得的次数。
import java.util.*;
public class PRS {
public static Scanner kbd = new Scanner(System.in);
public static void instructions() {
System.out.println("\nThis is the popular game of paper, rock, scissors. Enter your"
+ "\nchoice by typing the word \"paper\", the word \"rock\" or the word"
+ "\n\"scissors\". The computer will also make a choice from the three"
+ "\noptions. After you have entered your choice, the winner of the"
+ "\ngame will be determined according to the following rules:"
+ "\n\nPaper wraps rock (paper wins)"
+ "\nRock breaks scissors (rock wins)"
+ "\nScissors cuts paper (scissors wins)"
+ "\n\nIf both you and the computer enter the same choice, then the game "
+ "\nis tied.\n");
}
public static int playGame(){
int outcome = 0;
System.out.print("Enter your choice: ");
kbd = new Scanner(System.in);
String player = kbd.nextLine().toLowerCase();
String computerChoice = computerChoose();
System.out.println("\nYou entered: " + player);
System.out.println("Computer Chose: " + computerChoose());
if(player.equals(computerChoose())){
outcome = 3;
}
else if (player.equals("paper") && computerChoice.equals("rock")){
outcome = 1;
}
else if (computerChoice.equals("paper") && player.equals("rock")){
outcome = 2;
}
else if (player.equals("rock") && computerChoice.equals("scissors")){
outcome = 1;
}
else if (computerChoice.equals("rock") && player.equals("scissors")){
outcome = 2;
}
else if (player.equals("scissors") && computerChoice.equals("paper") ){
outcome = 1;
}
else if (computerChoice.equals("scissors") && player.equals("paper")){
outcome = 2;
}
else if (player.equals("rock") && computerChoice.equals("paper") ){
outcome = 2;
}
else if (computerChoice.equals("rock") && player.equals("paper")){
outcome = 1;
}
return outcome;
}
public static String computerChoose(){
/*return "scissors";*/
Random generator = new Random();
String [] answer = new String [3];
answer [0]= "paper";
answer [1] = "rock";
answer [2] = "scissors";
return answer[generator.nextInt(3)];
}
public static void main(String[] args) {
kbd = new Scanner(System.in);
System.out.println("THE GAME OF PAPER, ROCK, SCISSORS:");
System.out.print("\nDo you need instructions (Y or N)? ");
String userPlay = kbd.nextLine();
if (userPlay.equalsIgnoreCase("y")){
instructions();
}
String answer;
do{
int result = playGame();
System.out.println(result);
switch (result){
case 1:
System.out.println("YOU WIN!");
break;
case 2:
System.out.println("Comp WINs!");
break;
case 3:
System.out.println("IT'S A TIE!");
break;
default:
}
System.out.print("\nPlay again ( Y or N)? ");
answer = kbd.nextLine();
}while(answer.equalsIgnoreCase("y"));
}
}
答案 0 :(得分：4)
您需要做的第一件事就是只调用computerChoose()一次。每次调用此方法时，它都会生成一个新的随机数，因此会产生不同的答案。您只应在playGame()内调用一次，并将其分配给本地变量。
E.g。
String computerChoice = computerChoose();
然后使用此变量名称替换您对computerChoose()的所有其他调用。这样，您将显示一个值，并仅比较逻辑中的一个值。
至于跟踪其他信息，例如游戏数量和获胜/失败的数量，请考虑声明更多的类变量（或主方法中的局部变量），然后您可以分配，增加和读取。您可以在main方法的do-while循环中完成所有这些操作。不需要任何额外的循环。
答案 1 :(得分：1)
除了Adam的答案之外，将末尾的do-while循环更改为以下内容将解决一些不同的问题。
String answer;
int winCount=0, lossCount=0, tieCount=0;
do{
int result = playGame();
switch (result){
case 1:
System.out.println("YOU WIN!");
winCount++;
break;
case 2:
System.out.println("Comp WINs!");
lossCount++;
break;
case 3:
System.out.println("IT'S A TIE!");
tieCount++;
break;
default:
}
System.out.print("\nPlay again ( Y or N)? ");
answer = kbd.nextLine();
}while(answer.equalsIgnoreCase("y"));
System.out.printf("Wins: %d, Losses: %d, Total plays: %d%n", winCount, lossCount, winCount+lossCount+tieCount);
您需要在while循环中更新result，否则只有第一个游戏的结果才会准确。