我有ArrayList<Clause>
名为listtable
。出于某种原因Clause[] whatever = listtable.toArray()
提供了不兼容的类型错误,但Clause[] whatever = listtable.toArray(new Clause[0])
工作得很好。为什么会这样?这两个电话有什么区别? javadoc说他们“功能相同”。
这是我的完整代码(相关陈述在结束之前):
public static Clause[] readCNF(String name,Boolean print) throws IOException
{
BufferedReader file = new BufferedReader(new FileReader("./" + name));
ArrayList<Clause> listtable = new ArrayList<Clause>();
String line = null;
while ((line = file.readLine()) != null) {
if(line.charAt(0) == 'p')
{
Scanner scanner = new Scanner(line);
scanner.next(); scanner.next(); Clause.NumVars = scanner.nextInt(); Clause.NumClauses = scanner.nextInt();
} else if(line.charAt(0) != 'c') {
ArrayList<Integer> lits = new ArrayList<Integer>();
Scanner scanner = new Scanner(line);
while(scanner.hasNext())
{
int var = scanner.nextInt();
if(var != 0){ lits.add(var);}
}
listtable.add(new Clause(lits));
}
}
if(print) {
for(Clause clause : listtable)
{
clause.print();
}
}
return(listtable.toArray(new Clause[0])); //since the return type is Clause[] this is the same as the statements in the question
}
答案 0 :(得分:2)
toArray()
返回Object
数组。您必须将数组的每个元素转换为所需的类型。
toArray(T[])
接受泛型类型并返回特定类型的数组。无需转换返回值和/或数组元素。
正如上面的评论所述,toArray()
方法来自仿制药。
List<String> list = new ArrayList<String>();
list.add("Alice");
list.add("Bob");
String[] strArray = list.toArray(new String[0]);
for (String str : strArray) {
System.out.println(str);
}
Object[] objArray = list.toArray();
for (Object obj : objArray) {
String str = (String) obj;
System.out.println(str);
}