生成扑克牌的所有不同的7张牌组合?

时间:2014-10-26 16:37:59

标签: c# combinations permutation poker

我正在尝试生成扑克牌的所有不同组合,如下所述:

Generating all 5 card poker hands

但我一直卡住了。当在上面的URL上尝试NickLarsen的C#答案时,我在第49行遇到了未处理的异常错误。(https://stackoverflow.com/a/3832781/689881

我想要的是非常简单:生成所有卡片组合并在简单的.txt文件中一次打印一行

另外,我实际上想要所有7张卡组合(而不是5张)。 例如,前两行可能如下所示:

2c2d2h2s3c3d3h
2c2d2h2s3c3d3s

我如何实现这一目标?速度并不重要。

以下是来自NickLarsen(我的修改)的代码失败:

using System;
using System.Collections.Generic;
using System.Linq;

namespace ConsoleApplication20
{
struct Card
{
    public int Suit { get; set; }
    public int Rank { get; set; }
}

class Program
{
    static int ranks = 13;
    static int suits = 4;
    static int cardsInHand = 7;

    static void Main(string[] args)
    {
        List<Card> cards = new List<Card>();
        //cards.Add(new Card() { Rank = 0, Suit = 0 });
        int numHands = GenerateAllHands(cards);

        Console.WriteLine(numHands);
        Console.ReadLine();
    }

    static int GenerateAllHands(List<Card> cards)
    {
        if (cards.Count == cardsInHand) return 1;

        List<Card> possibleNextCards = GetPossibleNextCards(cards);

        int numSubHands = 0;

        foreach (Card card in possibleNextCards)
        {
            List<Card> possibleNextHand = cards.ToList(); // copy list
            possibleNextHand.Add(card);
            numSubHands += GenerateAllHands(possibleNextHand);
        }

        return numSubHands;
    }

    static List<Card> GetPossibleNextCards(List<Card> hand)
    {
        int maxRank = hand.Max(x => x.Rank);

        List<Card> result = new List<Card>();

        // only use ranks >= max
        for (int rank = maxRank; rank < ranks; rank++)
        {
            List<int> suits = GetPossibleSuitsForRank(hand, rank);
            var possibleNextCards = suits.Select(x => new Card { Rank = rank, Suit = x });
            result.AddRange(possibleNextCards);
        }

        return result;
    }

    static List<int> GetPossibleSuitsForRank(List<Card> hand, int rank)
    {
        int maxSuit = hand.Max(x => x.Suit);

        // select number of ranks of different suits
        int[][] card = GetArray(hand, rank);

        for (int i = 0; i < suits; i++)
        {
            card[i][rank] = 0;
        }

        int[][] handRep = GetArray(hand, rank);

        // get distinct rank sets, then find which ranks they correspond to
        IEnumerable<int[]> distincts = card.Distinct(new IntArrayComparer());

        List<int> possibleSuits = new List<int>();

        foreach (int[] row in distincts)
        {
            for (int i = 0; i < suits; i++)
            {
                if (IntArrayComparer.Compare(row, handRep[i]))
                {
                    possibleSuits.Add(i);
                    break;
                }
            }
        }

        return possibleSuits;
    }

    class IntArrayComparer : IEqualityComparer<int[]>
    {
        #region IEqualityComparer<int[]> Members

        public static bool Compare(int[] x, int[] y)
        {
            for (int i = 0; i < x.Length; i++)
            {
                if (x[i] != y[i]) return false;
            }

            return true;
        }

        public bool Equals(int[] x, int[] y)
        {
            return Compare(x, y);
        }

        public int GetHashCode(int[] obj)
        {
            return 0;
        }

        #endregion
    }

    static int[][] GetArray(List<Card> hand, int rank)
    {
        int[][] cards = new int[suits][];
        for (int i = 0; i < suits; i++)
        {
            cards[i] = new int[ranks];
        }

        foreach (Card card in hand)
        {
            cards[card.Suit][card.Rank] = 1;
        }

        return cards;
    }
}
}

3 个答案:

答案 0 :(得分:2)

这是因为您已注释掉//cards.Add(new Card() { Rank = 0, Suit = 0 });。您的cards列表为空,而您的代码找不到空数组的max - 这是可预测的。

答案 1 :(得分:1)

我参加派对有点晚了,但有相同的需求(5张扑克牌)。另外在Nick Larsen的工作(看似不完美,因为我也得到了错误的数字)回答另一个线程,只需添加一个方法来获取卡的名称(我相信有人可以更优雅地做到这一点,但它有效):

    static string GetCardName(Card card)
    {
        string cardName;
        string cardFace;
        string cardSuit;

        switch (card.Rank)
        {
            case 0:
                cardFace = "2";
                break;
            case 1:
                cardFace = "3";
                break;
            case 2:
                cardFace = "4";
                break;
            case 3:
                cardFace = "5";
                break;
            case 4:
                cardFace = "6";
                break;
            case 5:
                cardFace = "7";
                break;
            case 6:
                cardFace = "8";
                break;
            case 7:
                cardFace = "9";
                break;
            case 8:
                cardFace = "10";
                break;
            case 9:
                cardFace = "J";
                break;
            case 10:
                cardFace = "Q";
                break;
            case 11:
                cardFace = "K";
                break;
            default:
                cardFace = "A";
                break; 
        }

        switch (card.Suit)
        {
            case 0:
                cardSuit = "H";
                break;
            case 1:
                cardSuit = "D";
                break;
            case 2:
                cardSuit = "S";
                break;
            default:
                cardSuit = "C";
                break;
        }

        cardName = cardFace + cardSuit;

        return cardName;
    }

然后,在for循环中使用它,这样你就可以打印出来或者你需要的东西:

    static void Main(string[] args)
    {
        List<Card> cards = new List<Card>();
        cards.Add(new Card() { Rank = 0, Suit = 0 });
        int numHands = GenerateAllHands(cards);
        int counter = 0;

        Console.WriteLine(numHands);
        Console.WriteLine(possibleHands.Count);

        foreach (Hand hand in possibleHands)
        {
            counter += 1;

            foreach (Card card in hand.Cards)
            {
                hand.HandString += GetCardName(card) + " ";
            }

            hand.HandString = hand.HandString.Trim();
        }

        Console.ReadLine();
    }

答案 2 :(得分:1)

这在大约3秒钟内完成 为什么要将它们写到文本文件中 您可以比从文件中读取的更快地生成它们

    public void PokerHands7from52()
    {
        for (byte i = 0; i < 52; i++)
            Debug.WriteLine("rank " + i % 13 + "  suite " + i / 13);

        Stopwatch sw = new Stopwatch();
        sw.Start();
        int counter = 0;
        for (int i = 51; i >= 6; i--)
        {
            for (int j = i - 1; j >= 5; j--)
            {
                for (int k = j - 1; k >= 4; k--)
                {
                    for (int m = k - 1; m >= 3; m--)
                    {
                        for (int n = m - 1; n >= 2; n--)
                        {
                            for (int p = n - 1; p >= 1; p--)
                            {
                                for (int q = p - 1; q >= 0; q--)
                                {
                                    // the 7 card are i, j, k, m, n, p, q
                                    counter++;
                                    if (counter % 10000000 == 0)
                                        Debug.WriteLine(counter.ToString("N0") + " " + sw.ElapsedMilliseconds.ToString("N0"));
                                }
                            } 
                        }

                    }
                }
            }
        }
        sw.Stop();
        System.Diagnostics.Debug.WriteLine("counter " + counter.ToString("N0") + "  should be 133,784,560");
        System.Diagnostics.Debug.WriteLine("sw " + sw.ElapsedMilliseconds.ToString("N0"));
    }
}