Question

以下代码导致AttributeError：'list'对象没有属性'strip'，我不知道如何解决它：

#!/usr/bin/env python
from __future__ import absolute_import, division, print_function
from itertools import groupby


DATA = [["Test", "A", "B01", 828288,  1,    7, 'C', 5],
        ["Test", "A", "B01", 828288,  1,    7, 'T', 6],
        ["Test", "A", "B01", 171878,  3,    7, 'C', 5],
        ["Test", "A", "B01", 171878,  3,    7, 'T', 6],
        ["Test", "A", "B01", 871963,  3,    9, 'A', 5],
        ["Test", "A", "B01", 871963,  3,    9, 'G', 6],
        ["Test", "A", "B01", 1932523, 1,   10, 'T', 4],
        ["Test", "A", "B01", 1932523, 1,   10, 'A', 5],
        ["Test", "A", "B01", 1932523, 1,   10, 'X', 6],
        ["Test", "A", "B01", 667214,  1,   14, 'T', 4],
        ["Test", "A", "B01", 667214,  1,   14, 'G', 5],
        ["Test", "A", "B01", 667214,  1,   14, 'G', 6]]


def iter_something(rows):
    key_names = ['type', 'name', 'sub_name', 'pos', 's_type', 'x_type']
    chr_key_names = ['letter', 'no']
    for keys, group in groupby(rows, lambda row: row[:6]):
        result = dict(zip(key_names, keys))
        result['chr'] = [dict(zip(chr_key_names, row[6:])) for row in group]
        yield result


def convert(val):
    constructors = [int, str]
    for c in constructors:
        try:
            return c(val)
        except ValueError:
            pass


def main():
    with open("/home/mic/tmp/test.txt") as f:
        parts = (line.split(',') for line in f)
        column = (part.strip() for part in parts)
        for object_ in iter_something(column):
            print(object_)


if __name__ == '__main__':
    main()

Answer 1

您已将行拆分为列：

parts = (line.split(',') for line in f)

然后尝试去除每个列列表：

column = (part.strip() for part in parts)

那不会奏效。而是删除每列：

column = ([col.strip() for col in part] for part in parts)

您可能希望使用csv module来执行从文件到数据行的转换，但是：

with open("/home/mic/tmp/test.txt", 'rb') as f:
    reader = csv.reader(f, skipinitialspace=True)
    for object_ in iter_something(reader):
        print(object_)

skipinitialspace选项可确保删除直接跟在分隔符后面的空格。当然，删除了每行末尾的换行符。

Answer 2

当您使用split创建列表时，

parts = (line.split(',') for line in f)在拆分时剥离：

parts = (line.strip().split(',') for line in f)

AttributeError：'list'对象没有属性'strip'

2 个答案: