我正在尝试读取一个文本文件,其中填充了格式如下的单个十六进制值:
0c 10 00 04 20 00 09 1a 00 20
我想要的是读取它们,转换为二进制,然后存储在向量中。我希望我的print语句输出如下:
00001100
00010000
00000000
00000100
00100000
00000000
00001001
00011010
00000000
00100000
我以为我正在正确阅读我的文件,但我似乎只能从每一行获得第一个十六进制值。例如:我只能在获取下一行之前读取0c,依此类推。如果有人能告诉我我做错了什么就会很棒。这是我的代码:
#include <iostream>
#include <fstream>
#include <string>
#include <sstream>
#include <vector>
#include <bitset>
using namespace std;
vector<bitset<8> > memory(65536);
int main () {
string hex_line;
int i = 0;
ifstream mem_read;
//Read text file
mem_read.open("Examplefile.txt");
if(mem_read.is_open()){
//read then convert to binary
while(getline(mem_read, hex_line)){
unsigned hex_to_bin;
stringstream stream_in;
cout << hex_line << '\n';
stream_in<< hex << hex_line;
stream_in >> hex_to_bin;
memory[i] = hex_to_bin;
i++;
}
}else{
cout << "File Read Error";
}
//print binaries
for(int j = 0; j < i; j++){
cout << memory[j] << '\n';
}
mem_read.close();
return 0;
}
答案 0 :(得分:1)
您只需将一个令牌输入字符串流:stream_in << hex_line
!
你的内循环应如下所示:
while (std::getline(mem_read, hex_line))
{
istringstream stream_in(hex_line);
for (unsigned hex_to_bin; stream_in >> hex >> hex_to_bin; )
{
memory[i] = hex_to_bin;
i++;
}
}
事实上,整个代码的大小可能会有所减少:
#include <bitset> // for std::bitset
#include <fstream> // for std::ifstream
#include <iostream> // for std::cout
#include <iterator> // for std::istream_iterator
#include <sstream> // for std::istringstream
#include <string> // for std::getline and std::string
#include <vector> // for std::vector
std::vector<std::bitset<8>> memory;
int main()
{
memory.reserve(65536);
std::ifstream mem_read("Examplefile.txt");
for (std::string hex_line; std::getline(mem_read, hex_line); )
{
std::istringstream stream_in(hex_line);
stream_in >> std::hex;
memory.insert(memory.end(),
std::istream_iterator<unsigned int>(stream_in), {});
}
for (auto n : memory) { std::cout << n << '\n'; }
}