Question

我需要一个异构的，类型安全的容器来存储不相关的类型A，B，C。

这是一种类型级别规范：

trait Container {
  putA(a: A) 
  putB(b: B)
  putC(c: C)
  put(o: Any) = { o match {
    case a: A => putA(a)
    case b: B => putB(b)
    case c: C => putC(c)
  }
  getAllAs : Seq[A]
  getAllBs : Seq[B]
  getAllCs : Seq[C]
}

哪种类型是支持此容器的最佳套件？

是否值得为类型A，B，C创建容错[T]类型类？

THKS。

Answer 1

正如其他人所说，你可以利用无形的＆＃39; Coproduct类型。这是一个例子。

// let's define a Coproduct of the two types you want to support
type IS = Int :+: String :+: CNil

// now let's have a few instances
val i = Coproduct[IS](42)
val i2 = Coproduct[IS](43)
val s = Coproduct[IS]("foo")
val s2 = Coproduct[IS]("bar")

// let's put them in a container
val cont = List(i, s, i2, s2)

// now, do you want all the ints?
val ints = cont.map(_.select[Int]).flatten

// or all the strings?
val strings = cont.map(_.select[String]).flatten

// and of course you can add elements (it's a List)
val cont2 = Coproduct[IS](12) :: cont
val cont3 = Coproduct[IS]("baz") :: cont2

现在，这当然不是通用容器最直观的API，但可以使用Coproduct轻松地将逻辑封装在自定义类中，以表示多种类型。

这是一个实现草图

import shapeless._; import ops.coproduct._

class Container[T <: Coproduct] private (underlying: List[T]) {
  def ::[A](a: A)(implicit ev: Inject[T, A]) =
    new Container(Coproduct[T](a) :: underlying)

  def get[A](implicit ev: Selector[T, A]) =
    underlying.map(_.select[A]).flatten

  override def toString = underlying.toString
}

object Container {
  def empty[T <: Coproduct] = new Container(List[T]())
}

实施例

scala> type IS = Int :+: String :+: CNil
defined type alias IS

scala> val cont = 42 :: "foo" :: "bar" :: 43 :: Container.empty[IS]
cont: Container[IS] = List(42, foo, bar, 43)

scala> cont.get[Int]
res0: List[Int] = List(42, 43)

scala> cont.get[String]
res1: List[String] = List(foo, bar)

Answer 2

Miles Sabin在unboxed union types写了一篇文章;这是在CoProduct库中shapeless实现的：

shapeless具有Coproduct类型，Scala Either对任意数量的选择的推广

我绝对不是无形的专家，但如果您使用无形标记创建新问题或编辑您的问题，那么使用CoProduct

可以获得所需的任何帮助

Answer 3

你应该看看Shapeless的HList或Coproduct;我不会自己重塑这个。

Answer 4

这是第一个版本，但我想抽象出类型：

trait Container {

  def putInt(i: Int)
  def putString(s: String)
  def put(o: Any) = o match {
    case i: Int => putInt(i)
    case s: String => putString(s)
  }
  def getInts() : Seq[Int]
  def getStrings() : Seq[String]

}

class MutableContainer extends Container {

  val ints = mutable.ArrayBuffer[Int]()
  val strings = mutable.ArrayBuffer[String]()

  override def putInt(i: Int): Unit = ints += i

  override def putString(s: String): Unit = strings += s

  override def getStrings(): Seq[String] = strings

  override def getInts(): Seq[Int] = ints

}

object TestContainer extends App {
  val mc = new MutableContainer()
  mc.put("a")
  mc.put("b")
  mc.put(1)
  println(mc.getInts())
  println(mc.getStrings())
}

现在尝试抽象出类型

trait Container {
  def getInts() : Seq[Int]
  def getStrings() : Seq[String]

  def put[T](t: T)
  //def get[T] : Seq[T]
}

class MutableContainer extends Container {
  val entities = new mutable.HashMap[Class[_], mutable.Set[Any]]() with mutable.MultiMap[Class[_], Any]

  override def getStrings(): Seq[String] = entities.get(classOf[String]).map(_.toSeq).getOrElse(Seq.empty).asInstanceOf[Seq[String]] //strings
  override def getInts(): Seq[Int] = entities.get(classOf[Int]).map(_.toSeq).getOrElse(Seq.empty).asInstanceOf[Seq[Int]]

  //override def get[T]: Seq[T] = entities.get(classOf[T]).map(_.toSeq).getOrElse(Seq.empty).asInstanceOf[Seq[T]]
  override def put[T](t: T): Unit = entities.addBinding(t.getClass, t)
}

trait Containable[T] {
  def typ : String
}

trait Cont {
  implicit object IntContainable extends Containable[Int] {
    override def typ: String = "Int"
  }
  implicit object StringContainable extends Containable[String] {
    override def typ: String = "String"
  }
}

object TestContainer extends App {
  val mc = new MutableContainer()
  mc.put("a")
  mc.put("b")
  mc.put(1)
  println(mc.getInts())
  println(mc.getStrings())
  println(mc.entities.keys)
}

但是我遇到了java.lang.Integer和Int ...

的问题

如何在Scala中实现异构容器

4 个答案: